PHP JSON string converted to an array or object

The web-based approach is to use Get_object_vars to convert the class type to an array and then use the foreach traversal to

$array = Get_object_vars ($test);

$json = ' [{' id ': ' 1 ', ' name ': ' \u5f20\u96ea\u6885 ', ' age ': ', ' subject ': ' \u8ba1\u7b97\u673a\u79d1\u5b66\u4e0e\u6280 \u672f "},{" id ":" 2 "," Name ":" \u5f20\u6c9b\u9716 "," Age ":" + "," Subject ":" \U8F6F\U4EF6\U5DE5\U7A0B "}] ';

The first thing to do is to encode the JSON-formatted string with Json_decode,

$students = Json_decode ($json);

Directly in PHP file with $students:

for ($i =0; $i <count ($students); $i + +) {
echo "Name:". $students [$i] [' name ']. " Age: ". $students [$i] [' ages ']." Major: ". $students [$i] [' Subject ']." <br/> ";
}

The error is as follows:

Fatal Error: Cannot use Objectof type StdClass as array in D:\wamp\www\test.phpon line

Print $students:

Var_dump ($students);

Will output:

Array (2) {

[0]=>

Object (StdClass) #2 (4) {

["id"]=> string (1) "1"

["Name"]=> string (9) "Ms. Zhang"

["Age"]=> string (2) "27"

object (StdClass) #3 (4) {This means that the converted JSON string goes to an object rather than an array, see the following red background word

["Subject"]=>string (24) "Computer Science and Technology"

}

[1]=>

["id"]=> string (1) "2"

["Name"]=> string (9) "Zhang Yi-lin"

["Age"]=> string (2) "21"

["Subject"]=> string (12) "Software Engineering"

}

}

Visible, the returned result is an object instead of an array. should be accessed as an object:

foreach ($students as $obj) {
echo "Name:". $obj->name. " Age: ". $obj->age." Major: ". $obj->subject." <br/> ";
}

The output is:

Name: Ms. Zhang Age: 27 Major: Computer Science and technology
Name: Zhang Yi-lin Age: 21 Major: Software engineering

MixedJson_decode (String$json [, Bool$assoc])

Description: Accepts a JSON-formatted string and converts it to a PHP variable.

Json_decode can receive two parameters:

JSON: The JSONstring format to be decoded.

Assoc: When this argument is TRUE, an array is returned instead of an object.

$students = Json_decode ($json, true);

Then print the $students:

Var_dump ($students);

Output:

Array (2) {

[0]=>

Array (4) {

["id"]=> string (1) "1"

["Name"]=> string (9) "Ms. Zhang"

["Age"]=> string (2) "27"

["Subject"]=>string (24) "Computer Science and Technology"

}

[1]=>

Array (4) {

["id"]=> string (1) "2"

["Name"]=> string (9) "Zhang Yi-lin"

["Age"]=> string (2) "21"

["Subject"]=>string (12) "Software Engineering"

}

}

At this point, $students is the number of groups, you can directly use:

for ($i =0; $i <count ($students); $i + +) {
echo "Name:". $students [$i] [' name ']. " Age: ". $students [$i] [' ages ']." Major: ". $students [$i] [' Subject ']." <br/> ";
}

The output is:

Name: Ms. Zhang Age: 27 Major: Computer Science and technology
Name: Zhang Yi-lin Age: 21 Major: Software engineering

Summarize:

There are two ways to work with JSON-formatted strings in PHP code:

Method One:

$json = ' [{' id ': ' 1 ', ' name ': ' \u5f20\u96ea\u6885 ', ' age ': ', ' subject ': ' \u8ba1\u7b97\u673a\u79d1\u5b66\u4e0e\u6280 \u672f "},{" id ":" 2 "," Name ":" \u5f20\u6c9b\u9716 "," Age ":" + "," Subject ":" \U8F6F\U4EF6\U5DE5\U7A0B "}] ';

$students = Json_decode ($json);//Get an Object

foreach ($studentsas $obj) {

echo "Name:". $obj->name. " &nbsp;&nbsp;&nbsp; Age: ". $obj->age." &nbsp;&nbsp;&nbsp; major: ". $obj->subject." <br/> ";
}

Method Two:

$json = ' [{' id ': ' 1 ', ' name ': ' \u5f20\u96ea\u6885 ', ' age ': ', ' subject ': ' \u8ba1\u7b97\u673a\u79d1\u5b66\u4e0e\u6280 \u672f "},{" id ":" 2 "," Name ":" \u5f20\u6c9b\u9716 "," Age ":" + "," Subject ":" \U8F6F\U4EF6\U5DE5\U7A0B "}] ';

$students = Json_decode ($json, true);//Get an array

for ($i =0; $i <count ($students); $i + +) {
echo "Name:". $students [$i] [' name ']. " &nbsp;&nbsp;&nbsp; Age: ". $students [$i] [' ages ']." &nbsp;&nbsp;&nbsp; major: ". $students [$i] [' Subject ']." <br/> ";
}

PHP JSON string converted to an array or object