Php obtains the value of & amp; in url parameters. In actual projects, we often encounter the path to get the previous page address. You can return to the previous page and copy the code as follows: scriptwindow. history. go (-1); in actual project process, we often encounter the path to obtain the previous page address. You can return to the previous page to use
The code is as follows:
Script window. history. go (-1); script
This is operated through JS.
In such a scenario, when the user needs to exit the account, you want him to exit directly on the current page
For example, the current page address is http: // xxx/module. php? Module = groupbook & view = index & id = 2.
When you exit the system, you must use $ _ SERVER ['request _ URI '] to obtain the current path, and then pass this value as a parameter to the path to be returned for exit.
He only obtained http: // xxx/module. php? Module = groupbook does not get & view = index & id = 2, which means the address returned after we exit is changed
Http: // xxx/module. php? Module = groupbook (this should be http: // xxx/module. php? Module = groupbook & view = index & id = 2 ),
This is because he regards & as the first parameter, which is simply understood
Http: // xxx/login. php? Op = logout & return = http: // xxx/module. php? Module = groupbook & view = index & id = 2,
Changed
Http: // xxx/login. php? Op = logout & return = http: // xxx/module. php? Module = groupbook & view = index & id = 2.
In this case, you need to use urlencode ($ _ SERVER ['request _ URI ']) to transcode the currently obtained $ _ SERVER ['request _ URI'].
We can solve our problem.
Bytes. You can return to the previous page using the following code: scriptwindow. history. go (-1);/script this...
