PHP upload pictures, delete pictures Simple instance _php instance

Simple PHP upload picture, delete picture implementation code

Upload Picture:

 if (!empty ($_files["img" ["name"])) {//Extract file Domain content name and judge $path = "uppic/";//upload path if (!file_exists 
($path)) 
{//Check if there is a folder, if it is not created, and give the highest permission mkdir ("$path", 0700); 
}//end IF//Allow uploaded file format $tp = Array ("Image/gif", "Image/pjpeg", "image/jpeg"); Check to see if the upload file is in the allowed upload type if (!in_array ($_files["img"] ["type"], $TP)) {echo "<script>alert (' malformed '); History.go (-1); 
</script> "; 
Exit 
}//end IF $filetype = $_files[' img ' [' type ']; 
if ($filetype = = ' Image/jpeg ') {$type = '. jpg '; 
} if ($filetype = = ' image/jpg ') {$type = '. jpg '; 
} if ($filetype = = ' Image/pjpeg ') {$type = '. jpg '; 
if ($filetype = = ' Image/gif ') {$type = '. gif '; } if ($_files["img" ["name"]) {$today =date ("Ymdhis");//Get time and assign value to variable $file 2 = $path. $today. $type//Picture full path $img = $tod Ay. $type; 
Picture name $flag = 1; 
}//end if ($flag) $result =move_uploaded_file ($_files["img"] ["Tmp_name"], $file 2); Special note Here The first parameter passed to Move_uploaded_file is the temporary file uploaded to the server}//end IF//Here then writes the $img value to the corresponding field in the database 

To delete a picture:

Unlink ("uppic/". $img); Of course, the value of the variable is read from the database, php delete pictures more concise than the ASP

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