[POJ 2762] Going from u to v or from v to u? (Strongly connected component + topological sorting)
Description
In order to make their sons brave, Jiajia and Wind take them to a big cave. the cave has n rooms, and one-way corridors connecting some rooms. each time, Wind choose two rooms x and y, and ask one of their little sons go from one to the other. the son can either go from x to y, or from y to x. wind promised that her tasks are all possible, but she actually doesn' t know how to decide if a task is po Ssible. to make her life easier, Jiajia decided to choose a cave in which every pair of rooms is a possible task. given a cave, can you tell Jiajia whether Wind can randomly choose two rooms without worrying about anything?
Input
The first line contains a single integer T, the number of test cases. And followed T cases.
The first line for each case contains two integers n, m (0 <n <1001, m <6000), the number of rooms and corridors in the cave. the next m lines each contains two integers u and v, indicating that there is a corridor connecting room u and room v directly.
Output
The output shoshould contain T lines. Write 'yes' if the cave has the property stated above, or 'no' otherwise.
Sample Input
13 31 22 33 1
Sample Output
Yes
Source
POJ Monthly -- 2006.02.26, zgl & twb
A directed graph is given to determine whether u and v can reach v or u at any two points in the graph. If Yes, Yes is output and No is output.
Note that here is or is not. If yes, you can directly determine whether the entire graph is a strongly connected component. This is much simpler, the idea of this question is to first scale down the entire graph (any two points in each strongly connected component can be reached), and then sort the DAG after the scale-in, in the sorting process, if there are multiple zero entry points, the sorting fails. If the final Topology Sorting is successful, it indicates any two points u in the figure, v can reach v from u or from v to u
# Include
# Include
# Define MAXV 8010 # define MAXE 2010 # define cls (array, num) memset (array, num, sizeof (array) using namespace std; struct edge {int u, v, next;} edges [MAXV], newedges [MAXV]; int head [MAXE], dfn [MAXE], low [MAXE], belong [MAXE], stack [4 * MAXE], inDegree [MAXE]; bool inStack [MAXE]; int top = 0, nCount = 0, newCount = 0, tot = 0, index = 0, n, m; int min (int a, int B) {if (
1) return false; int rest = tot, result [MAXE]; while (rest --) {ans = 0; for (int p = head [num]; p! =-1; p = newedges [p]. next) {int v = newedges [p]. v; inDegree [v] --; if (inDegree [v] = 0) {ans ++; num = v ;}} if (ans> 1) return false ;} return true;} int main () {int testCase; cin> testCase; while (testCase --) {cls (head,-1); cls (dfn, 0 ); cls (low, 0); cls (stack, 0); cls (inStack, 0); cls (belong, 0); cls (inDegree, 0); top = 0, nCount = 0, newCount = 0, tot = 0, index = 0; for (int I = 0; I
> N> m; for (int I = 1; I <= m; I ++) {int a, B; cin> a> B; AddEdge (, b, edges, nCount) ;}for (int I = 1; I <= n; I ++) if (! Dfn [I]) tarjan (I); newGraph (); if (topologicalSort () cout <"Yes" <
Zookeeper