Poj-3660 Cow Contest

Source: Internet
Author: User

Poj-3660 Cow Contest

Link: www.bkjia.com

Use floyd to pass the closure to determine the outcome. In this way, all vertices a can reach are ranked after. All the points that can go to a are ranked before. For example, if the sum of "A", "ranking before" and "ranking after" is "n-1", the ranking is definite.

 

 

#include 
 
  #include 
  
   #include 
   
    #include 
    
     #include 
     
      using namespace std;const int MAX = 110;int n,m;int rank[MAX][MAX];int in[MAX] ,out[MAX];int ans;int main (){    int a,b;    while (cin>>n>>m)    {        memset(rank,0,sizeof(rank));        memset(in,0,sizeof(in));        memset(out,0,sizeof(out));        ans = 0;        while (m--)        {            cin>>a>>b;            rank[a][b] = 1;        }        for(int k=1;k<=n;k++)            for(int i=1;i<=n;i++)            for(int j=1;j<=n;j++)        {            if (rank[i][k] == 1 && rank[k][j] == 1)                rank[i][j] =1;        }        for(int i=1;i<=n;i++)        {            int res = 0;            for(int j=1;j<=n;j++)                res += rank[i][j] + rank[j][i];            if (res == n-1)                ans++;        }        cout<
      

 

 

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