POJ C Programming Advanced programming problem #4:tomorrow never knows?

Source: Internet
Author: User

Source: POJ (Coursera statement: The exercises completed on POJ will not count against the final results of Coursera. )

Note: Total time limit: 1000ms memory limit: 65536kB

Description

The Beetle's "a Day" and "Tomorrow Never Knows" are popular, if you tell you A day in the life, will it really be tomorrow never knows? believe that after learning this is not a problem, and now come to realize it 。

Reads a date in a format of YYYY-MM-DD (that is, the year-month-day), outputting the date of the day next to this date. You can assume that the date entered is not earlier than 1600-01-01, or later than 2999-12-30.

input

Enter only one row, formatted as a yyyy-mm-dd date.

Output

The output is also only one row, formatted as a YYYY-MM-DD date

Sample Input
2010-07-05
Sample Output
2010-07-06
Tips

The standard for leap years:

(1) The average year can be divisible by 4 and not divisible by 100 for leap years. (For example, 2004 is a leap year, 1901 is not a leap)

Earth Revolution

(2) century can be divisible by 400 is a leap year. (as 2000 is a leap year, 1100 is not a leap year)

The input statement scanf ("%d-%d-%d", &y,&m,&d) can be stored for years, months, and days. The output statement is formatted like printf ("%d-%02d-%02d\n", Year,month,day).

1#include <iostream>2#include <stdio.h>3 intIsleapyear (intYear );4 intMain ()5 {6     inty,m,d;7     intYear,month,day;8     intMonthcarrysave=0;9     intYearcarrysave=0;Tenscanf"%d-%d-%d",&y,&m,&d); One     if(m==1|| m==3|| m==5|| m==7|| m==8|| m==Ten|| m== A){ A         if(d== to){ -day=1; -Monthcarrysave=1; the         } -         ElseDay=d+1; -     } -     Else { +         if(m==2){ -             if(d== -){ +                 if(Isleapyear (y)) { Aday=1; atMonthcarrysave=1;  -                 }   -                 Else{ -Day=d+1;  -                 } -             } in             Else if(d== in){ -day=1; toMonthcarrysave=1; +             } -             Else{ theDay=d+1; *             } $         }Panax Notoginseng         Else{ -             if(d== -){ theday=1; +Monthcarrysave=1; A             } the             Else { +Day=d+1; -             } $         } $     } -month=m+Monthcarrysave; -     if(month> A){ theMonth=1; -Yearcarrysave=1;Wuyi     }  theyear=y+Yearcarrysave; -printf"%d-%02d-%02d\n", year,month,day); Wu     return 0; - } About intIsleapyear (intYear ) $ { -     if(year%4==0&&year% -!=0|| year% -==0) -         return 1; -     Else return 0; A}

POJ C Programming Advanced programming problem #4:tomorrow never knows?

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