Pool quantity (nyoj27) (BFS)

Source: Internet
Author: User

Pool quantity (nyoj27) (BFS)
Pool quantity time limit: 3000 MS | memory limit: 65535 KB difficulty: 4

Description
There are some small rivers and some lakes on the campus of Nanyang Institute of Technology. Now we take them all as pools. Suppose there is a map somewhere in our school, this map only identifies whether it is a pool. Now, your task is coming. Please use a computer to figure out several pools in the map.
Input
Enter an integer N in the first line, indicating that there are N groups of test data.
For each set of data, the number of rows of the map is first input m (0 Output
Output The number of pools in the map.
Note that, if the pool is still located next to each pool (up or down the four locations), they can be seen as the same pool.
Sample Input
23 41 0 0 0 0 0 1 11 1 1 05 51 1 1 1 00 0 1 0 10 0 0 0 01 1 1 0 00 0 1 1 1
Sample output
23
Source
[Zhang yuncong] original
Uploaded

Zhang yuncong

# Include
     
      
# Include
      
       
Int s [105] [105]; int a [4] = {0, 0, 1,-1}; // search in four directions. Int B [4] = {1,-1, 0}; void bfs (int x, int y) {int k, v, t; s [x] [y] = 0; for (k = 0; k <4; k ++) {v = x + a [k]; t = y + B [k]; if (s [v] [t]) {bfs (v, t) ;}} int main () {int test, n, m, I, j, ans; scanf ("% d", & test); while (test --) {scanf ("% d", & m, & n); memset (s, 0, sizeof (s); for (I = 1; I <= m; I ++) {for (j = 1; j <= n; j ++) scanf ("% d", & s [I] [j]);} for (I = 1, ans = 0; I <= m; I ++) {for (j = 1; j <= n; j ++) if (s [I] [j]) {bfs (I, j); ans ++;} printf ("% d \ n", ans);} return 0 ;}
      
     

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