Precautions for C ++ struct Programming

Source: Internet
Author: User

# Include <iostream. h>

Struct structa


Int imember;

Char * cmember;



Int main (INT argc, char * argv [])


Structa instant1, instant2;

Char c = 'a ';

Instant1.imember = 1;

Instant1.cmember = & C;

Instant2 = instant1;

Cout <* (instant1.cmember) <Endl;

* (Instant2.cmember) = 'B ';

Cout <* (instant1.cmember) <Endl;

Return 0;




The reason is that the instant2 = instant1 value assignment statement uses variable copy one by one, which causes their cmember to point to the same piece of memory.

In C, When pointer members exist in the struct, note that when using the value assignment statementWhether to direct the pointer from the two instances to the same memory address

In C ++, when a pointer member exists in the struct, we needOverride the copy constructor of struct and reload the '=' operator.


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