1, please use the code to achieve: the use of underline the list of each element of the mosaic into a string, li=[' Alex ', ' Eric ', ' rain '
l1=['Alex'Eric'rain' Print('%s_%s_%s'% (l1[0],l1[1],l1[2))
l1=['Alex','Eric','rain' n="_". Join (L1)print(n)
2. Find the elements in the list, remove the spaces for each element, and look for all elements that begin with a or a and end with C.
Li = ["Alec", "Aric", "Alex", "Tony", "Rain"]
Tu = ("Alec", "Aric", "Alex", "Tony", "Rain")
DiC = {' K1 ': ' Alex ', ' K2 ': ' Aric ', ' K3 ': ' Alex ', ' K4 ': ' Tony '}
3, write code, such as the following table, as required to achieve each function
li=[' Alex ', ' Eric ', ' rain '
- Calculates the list length and outputs
- Append the element "seven" to the list and output the added list
- Please insert the element "Tony" in the 1th position of the list and output the added list
- Please modify the element in the 2nd position of the list to "Kelly" and output the modified list
- Please remove the element "Eric" from the list and output the modified list
- Delete the 2nd element in the list and output the value of the deleted element and the list after the element is deleted
- Delete the 3rd element in the list and output the list after the element is deleted
- Delete the 2nd to 4th element in the list and output the list after the element is deleted
- Invert all the elements in the list and output the inverted list
- Please use the index of the for, Len, range output list
- Use Enumrate to output list elements and ordinal numbers (starting from 100)
- Use the For loop to output all the elements of the list
#calculates the list length and outputsl1=['Alex','Eric','Rain']Print(len (L1))#Append the element "seven" to the list and output the added listL1 = ['Alex','Eric','Rain']l1.append ('Seven')Print(L1)#Please insert the element "Tony" in the 1th position of the list and output the added listL1 = ['Alex','Eric','Rain']l1.insert (0,'Tony')Print(L1)#please modify the element in the 2nd position of the list to "Kelly" and output the modified listL1 = ['Alex','Eric','Rain']l1[1]='Kelly'Print(L1)#Please remove the element "Eric" from the list and output the modified listL1 = ['Alex','Eric','Rain']l1.remove ('Eric')Print(L1)#Delete the 2nd element in the list and output the value of the deleted element and the list after the element is deletedL1 = ['Alex','Eric','Rain']delL1[2]Print(L1)#Delete the 3rd element in the list and output the list after the element is deletedL1 = ['Alex','Eric','Rain']delL1[2]Print(L1)#Delete the 2nd to 4th element in the list and output the list after the element is deletedL1 = ['Alex','Eric','Rain']delL1[1:4]Print(L1)#invert all the elements in the list and output the inverted listL1 = ['Alex','Eric','Rain']l1.reverse ()Print(L1)#Please use the index of the for, Len, range output listL1 = ['Alex','Eric','Rain'] forIinchRange (len (L1)):Print. IO#use enumrate to output list elements and ordinal numbers (starting from 100)L1 = ['Alex','Eric','Rain'] forKvinchEnumerate (l1,100): Print(k,v)#use the For loop to output all the elements of the list forIinchL1:Print(i)
4, write code, such as the following table, please follow the functional requirements to achieve each function
Li = ["Hello", ' Seven ', ["Mon", ["H", "Kelly"], ' all '], 123, 446]
- Please output "Kelly" according to the index.
- Please use the index to find the ' all ' element and modify it to "all", such as: li[0][1][9] ...
Li = ["Hello",'Seven', ["Mon", ["h","Kelly"],' All'], 123, 446]#please output "Kelly" according to the index.Print(li[2][1][1])#Please use the index to find the ' all ' element and modify it to "all"Print(li[2][2]) li[2][2]=' All'Print(LI)
5, write code, there are the following tuple, please follow the functional requirements to achieve each of the functions
tu= (' Alex ', ' Eric ', ' Rain ')
- Computes the tuple length and outputs
- Gets the 2nd element of a tuple and outputs
- Gets the 第1-2个 element of the tuple and outputs
- Please use the for output tuple element
- Use the index of the for, Len, and range output tuples
- Use the Enumrate output primitive element and ordinal (ordinal starting from 10)
Tu= ('Alex','Eric','Rain')#computes the tuple length and outputsPrint(Len (TU))#gets the 2nd element of a tuple and outputsPrint(tu[1])#gets the 第1-2个 element of the tuple and outputsPrint(Tu[1:3])#please use the for output tuple element forIinchTu:Print(i)#Use the index of the for, Len, and range output tuples forIinchrange (len (TU)):Print(i)#Use the enumrate output primitive element and ordinal (ordinal starting from 10) forIndex,iinchEnumerate (tu,10): Print(index,i)
6, there are the following variables, please implement the required functions
Tu = ("Alex", [One, one, a, {"K1": ' V1 ', "K2": ["Age", "name"], "K3": (11,22,33)}, 44])
- Describe the characteristics of Ganso
- Can the first element in the TU variable "alex" be modified?
- What type is the value of "K2" in the TU variable? Is it possible to be modified? If you can, add an element, "Seven", to the
- What type is the value of "K3" in the TU variable? Is it possible to be modified? If you can, add an element, "Seven", to the
7. Dictionaries
DiC = {' K1 ': "v1", "K2": "V2", "K3": [11,22,33]}
- Please loop out all the keys
- Please loop out all of the value
- Please loop out all the keys and value
- Please add a key-value pair in the dictionary, "K4": "V4", and output the added dictionary
- In the modified dictionary, the value of "K1" corresponds to "Alex", Output the modified dictionary
- Please append an element 44 to the value of the K3 to output the modified dictionary
- Please insert element 18 in the 1th position of the K3 corresponding value, output the modified dictionary
8. Conversion
- Convert string s = "Alex" to list
- Convert string s = "Alex" to Cheng Yuanju
- Convert list li = ["Alex", "seven"] to Narimoto Group
- Convert meta-progenitor tu = (' Alex ', ' seven ') to a list
- Converts the list li = ["Alex", "seven"] to a dictionary and the dictionary key increments backwards by 10
9. Element classification
There is a value set [11,22,33,44,55,66,77,88,99,90] that holds all values greater than 66 to the first key in the dictionary, and a value less than 66 to the value of the second key.
That is: {' K1 ': All values greater than 66, ' K2 ': All values less than 66}
10, the output product list, the user enters the serial number, displays the user to select the product
Product Li = ["Mobile phone", "Computer", "mouse pad", ' yacht ')
- Allow users to add items
- User input serial number display content
11, the user interactive display similar provinces and counties N-Level linkage choice
- Allow users to add content
- Allow users to choose to view a level of content
12. Enumerate all values for which the Boolean value is False
3. There are two lists
L1 = [11,22,33]
L2 = [22,33,44]
- Get a list of elements of the same content
- Gets a list of elements in L1 that are not in the L2
- Gets a list of elements in L2 that are not in the L3
- Get elements with different contents in L1 and L2
14. Use for loop and range output
- For loop from large to small output 1-100
- For loop from small to output 100-1
- While loop from large to small output 1-100
- While loop from small to output 100-1
15. Use for loop and range output 9 * 9 multiplication table
for in range (1,10): is in range (1,i+1): print(str (i) + " * "+str (j) +"="+str (i*j), end=") Print()
16, for the prime number within 100 and. (Programming Questions)
17. [1,3,2,7,6,23,41,24,33,85,56] from small to large (bubbling method) (programming)
python-Basic Exercise 2