Python Basics-Day 1 Assignment-three tier menu level three menus

Source: Internet
Author: User

Job Requirements

1. Run the program output first level menu

2. Select a Level menu item, output level two menu, output level three menu similarly

3. Menu data saved in file

4. Let the user choose whether or not to exit

5. There is a function to return to the top level menu

Scoring criteria:

Complete the job 2,85 with multi-layer nested while loop

Complete the assignment with only one layer of cycle 2,100 points

SAMPLE 1
data = {    'Beijing': {        'Haidian': {            'Five crossing': {                'Soho': {},                'NetEase': {},                'Google': {},            },            'Zhongguancun': {                'Iqiyi Art': {},                'Autohome': {},                'Youku': {},            },            'on the ground': {                'Baidu': {},            },        },        'changping': {            'Shahe': {                'Oldboy': {},                'Beihang University': {},            },            'Tin Tong Court': {},            'Huilongguan': {},        },        'Chaoyang': {},        'Dongcheng': {},    },    'Shanghai': {        "Huangpu": {            'People's square': {                'Fried Chicken Shop': {},            },        },        'Zhabei': {            'train station': {                'Ctrip': {},            },        },        'Pudong': {},    },    'Shandong': {},}exit_flag=False while  notExit_flag: forIinchData:Print(i)#into the dead loop .Choice= Input ("your option >>>:")    ifChoiceinchData: while  notExit_flag: forJinchData[choice]:Print("\ t", j) Choice2= Input ('your 2nd option >>>:')             while  notExit_flag: forKinchData[choice][choice2]:Print('\t\t', K) Choice3= Input ('your 3rd option >>>:')                ifChoice3inchData[choice][choice2]: forLinchData[choice][choice2][choice3]:Print('\t\t', L) Choice4= Input ("final, please input B for exit")                    ifChoice4 = ='b':                        Pass  #pass = = Do not do anything, must write otherwise error. As a placeholder                    elifChoice4 = ="Q": Exit_flag=TrueifChoice3 = ='b':                     Break                elifChoice3 = ="Q": Exit_flag=TrueifChoice2 = ='b':                 Break            elifChoice2 = ="Q": Exit_flag= True
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Python Basics-Day 1 Assignment-three tier menu level three menus

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