Python Call DLL

Python is not very efficient to run, but we can call C functions or DLLs to improve efficiency.

The following simple write a DLL:

MyDll.h

  1   #ifndef MYDLL   2   #define  mydll 3   #ifdef my_dll   4   #define  My_dll extern "C" _declspec (dllimport)   #else  Span style= "color: #008080;" > 6   #define  my_dll extern "C" _declspec (dllexport)  7   #endif   8   9  my_dll int   fun ();  10  # endif  

MyDll.cpp

1 #include"MyDll.h"234int fun () 5 {6     return Ten ; 7 }

The DLL file is then generated using Python to invoke the fun function.

1  fromcTYPESImportWindll2 3 4 defDllfun ():5Ll=cdll. LoadLibrary ("E:\\mydll.dll")6     returnLl.fun ()7 8 9 if __name__=="__main__":Ten     Print(Dllfun ())

Output Result:

>>>
10
>>>

Ps:

① encountered an error: OSError: [Winerror 193]%1 is not a valid WIN32 application, which is caused by the use of 64-bit Python, If you want to solve this problem you can use 32-bit Python or compile a 64-bit DLL (the former should be a more compatible solution).

② in fact, I originally wrote in the fun function is "std::cout<<" PRINT "<<std::endl;", but the operation results are not output, the specific reason is unclear.

③ if it is an API in _stdcall format, change Cdll to Windll, otherwise the parameter function will appear: Valueerror:procedure probably called with too many arguments (8 bytes in Excess).

Python Call DLL