Python Challenge Fun Challenge

No. 0 Pass

Http://www.pythonchallenge.com/pc/def/0.html

>>>print 2 * * 38274877906944L

The replacement URL is http://www.pythonchallenge.com/pc/def/274877906944.html

1th Pass

Http://www.pythonchallenge.com/pc/def/map.html

is a password, the letter moves backwards two bits, YZ becomes AB

#！ /usr/bin/env python# coding: utf-8# author: toddlerya# date: 2015-1-27alpha  = [' A ',  ' B ',  ' C ',  ' d ',  ' e ',  ' f ',  ' g ',  ' h ',  ' I ',  ' J ',   ' K ',  ' l ',  ' m ',  ' n ',          ' o ',  ' P ',   ' q ',  ' R ',  ' s ',  ' t ',  ' u ',  ' V ',  ' W ',  ' x ',  ' y ',  ' z ']goal  =  "" "g fmnc wms bgblr rpylqjyrc gr zw fylb.rfyrq ufyr  amknsrcpq ypc dmp. bmgle gr gl zw fylbgq glcddgagclr ylb  Rfyr ' Q&NBSP;UFW&NBSP;RFGQ&NBSP;RCVR&NBSP;GQ&NBSP;QM&NBSP;JMLE.SQGLE&NBSP;QRPGLE.KYICRPYLQ ()  gq  PCAMKKCLBCB.&NBSP;LMU&NBSP;YNNJW&NBSP;ML&NBSP;RFC&NBSP;SPJ. "" " alpha_dict = {' A ': 0,  ' C ': 2,  ' B ': 1,  ' e ': 4,  ' d ':  3,   ' G ': 6,  ' F ':  5,               ' i ': 8,  ' h ': 7,  ' K ': 10,  ' J ':  9 ,  ' m ': 12,  ' l ': 11,  ' O ': 14,                ' n ': 13,  ' q ': 16,  ' P ': 15,  ' s ':  18,   ' R ': 17,  ' u ': 20,  ' t ': 19,                ' W ': 22,  ' V ': 21,  ' y ': 24,  ' x ':  23,   ' z ': 25}result_dict = {0:  ' a ', 1:  ' B ', 2:  ' C ', 3:  ' d ',  4:  ' e ', 5:  ' f ', 6:  ' g ', 7:  ' h ',                8:  ' i ', 9:  ' j ', 10:  ' K ',  11:  ' l ', 12:  ' m ', 13:  ' n ', 14:  ' o ',                15:  ' P ', 16:  ' Q ', 17:  ' R ', 18:  ' s ', 19:  ' t ',  20:  ' u ',                21:  ' V ', 22:  ' W ', 23:  ' x ', 24:  ' y ', 25:  ' z '} #alpha_dict  =  dict ([  (alpha[i], i)  for i in range (0,26)] ) #result_dict  =  Dict ([  (I, alpha[i])  for i in range (0,26)] ) result_order = [] result = []for a in goal:    if a in alpha:         i = alpha_dict[a]         if i < 24:             j = i + 2             Result_order.append (j)         elif 24 == i:             j = 0             result_order.append (j)         elif 25 == i:             j = 1             result_order.append (j)           #print  result_orderfor r in result_order:    x  = result_dict[r]    result.append (x) #print  resultnum = 0for a  in goal:    if a in alpha_dict:         print result[num],        num += 1     else: &Nbsp;      print a, 

Clearance Password:

I h o p e y o u d i d n T t r a n s l a T e i t b y h a n d.

t h a t s W h a t c o m P u t e R S a r E F o r. D o i n g i t i n b y h a n d

i s i n E F f i c I e n t a n d t h a T ' s W H y t h i s t e x t i s s o l o n G.

U S i n g s t r i n G.   M a K e T r a n s () I s r e c o m m e n d e D. N o w a p p l y o n t h e u r L.

Follow the instructions to change the next, good concise ... I made the wheel and wrote it so ugly ...

#！ /usr/bin/env python# coding:utf-8# author:toddlerya# date:2015-1-27from string Import maketransin_string = "Abcdefghijk lmnopqrstuvwxyz "out_string =" Cdefghijklmnopqrstuvwxyzab "goal =" "G FMNC wms Bgblr RPYLQJYRC gr ZW fylb.rfyrq Ufyr AMKNSR CPQ ypc DMP. Bmgle GR GL ZW fylbgq glcddgagclr ylb rfyr ' q UFW rfgq rcvr GQ QM Jmle.sqgle QRPGLE.KYICRPYLQ () GQ PCAMKKCLBCB. LMU ynnjw ml RFC spj. "" " trans_string = Maketrans (in_string, out_string) print goal.translate (trans_string)

This side of the output is much more beautiful:

I hope you didnt translate it by hand.

Thats what computers is for. Doing it in by hand

is inefficient and that's why the this text was so long.

Using String.maketrans () is recommended. Now apply to the URL.

2nd Pass

Http://www.pythonchallenge.com/pc/def/ocr.html

From the tips to know, view the source code, find a comment

<!--

Find rare characters in the mess below:

-

<!--

%%[email protected]_$^__#) ^) &!_+]!*@&^}@[@%] ()%+$&[([email protected]%+%$*^@$^!+]!&_#) _*}{}}!} _]$[%}@[{[email protected] #_ ^{*

@##&{#&{&) *% (]{{([*}@[@&]+

......

-

#!/usr/bin/env python# coding:utf-8# author:toddlerya# date:2015-1-27# put the contents of the note into the Rare_char Rare_char = "" "%%[email        protected]_$^__#) ^) &!_+]!*@&^}@[@%] ()% omitted n line "" "TMP = []for i in Rare_char:if i in Tmp:pass else: Tmp.append (i) Print I, Rare_char.count (i)

The results of the operation are as follows:

[Email protected]:~/desktop$ python 3.py 1220% 6104$ 6046@ 6157_ 6112^ 6030# 6115] 6186& 6043! 6079+ 6066] 6152* 6034} 6105[6108 (6154{6046e 1q 1u 1a 1l 1i 1t 1y 1

You can see that the fewest characters are equality. This is the clearance code. Change the URL, the next pass

3rd Pass

Http://www.pythonchallenge.com/pc/def/equality.html

Python Challenge Fun Challenge