Python checks whether the string is correct ISBN

This article describes how to check whether a string is an ISBN in python, and describes how to operate a string in Python, for more information about how to check whether the string is ISBN, see the example in this article. Share it with you for your reference. The specific implementation method is as follows:

def isISBN(isbn):   """Checks if the passed string is a valid ISBN number."""   if len(isbn) != 10 or not isbn[:9].isdigit():     return False   if not (isbn[9].isdigit() or isbn[9].lower() == "x"):     return False   tot = sum((10 - i) * int(c) for i, c in enumerate(isbn[:-1]))   checksum = (11 - tot % 11) % 11   if isbn[9] == 'X' or isbn[9] == 'x':     return checksum == 10   else:     return checksum == int(isbn[9]) ok = """031234161X 0525949488 076360013X 0671027360 0803612079     0307263118 0684856093 0767916565 0071392319 1400032806 0765305240""" for code in ok.split():   assert isISBN(code) bad = """0312341613 052594948X 0763600138 0671027364 080361207X 0307263110      0684856092 0767916567 0071392318 1400032801 0765305241 031234161      076530Y241 068485609Y""" for code in bad.split():   assert not isISBN(code) print "Tests of isISBN()passed." 

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