Python data structure: conversion exploration

Tag: Orm RoCE represents return Exce www. repr number www

*********************************First Part*************************************************************************************************************** # Enter the line number of Excel and output the ordinal number of the corresponding column (starting from 0) # Equivalent: 26 binary with A-Z to convert it to 10, namely: input a output 0, input B Output 1, input AA output 26 .... STRs = input (' Please enter a 1-2-letter string: '). lower () List_char = list (strs) sum = 0 def sub_str (str_a, Str_b): Return ord (str_a)-ord (St R_b) for index, str in enumerate (list_char[::-1]): Sum + = (sub_str (str, ' a ') +1) * * * * index print (sum-1) print (List_cha R[::-1]) *********************************Part II*************************************************************************************************************** Interpretation of the topic: that is a=0,z=25 z-a=25 according to the conversion of the system, Get the following formula: A = (a-a+1) *26^0-1 = 0Z = (z-a+1) *26^0-1 = 25AA = (a-a+1) *26^1 + (a-a+1) *26^0-1 = 26AZ = (a-a+1) *26^1 + (z-a+1) * 26^0-1 = 51BA = (b-a+1) *26^1 + (a-a+1) *26^0-1 = 52ZA = (z-a+1) *26^1 + (a-a+1) *26^0-1 = 26*26=676...............ZBFA = ( z-a+1) *26^3 + (b-a+1) *26^2 + (f-a+1) +26^1 + (a-a+) *26^0-1 if input: ZA, then List_char = [' Z ', ' A '], indexed to 0,1enumerate (list_char[::- 1] Reverse the list, i.e. [' A ', ' Z '], to reverse the index *********************************Part III*************************************************************************************************************** So, by this method, the hexadecimal output is decimal #!/usr/bin/ env/python35#-*-coding:utf-8-*-# Author:keekuun # 16 binary is every 16 into 1def distance (NUM1, num2): # Find the distance from the first number (0) if Ord (NUM1) >= 65:# input is a,b,c,d,e return ord (NUM1)-Ord (num2)-7else:# input is 0-9 return ord (NUM1)-Ord (NUM2) def sixteen_to_ten (num) : result = 0 for index, value in enumerate (Num[::-1]): # Converts each number of bits to 10, then sums result + = distance (value, str (' 0 ')) * 16 * * Index # print (' result=%s '%result) return result num = list (input (' 16 binary number (not added 0x): '). Upper ()) Print (Sixteen_to_ten ( num)) *********************************Fourth Part*************************************************************************************************************** **********************************************************************************

• Decimal: Decimal system, each bit up to 9, up to 10

• Binary: Binary system, each bit up to 1, up to 2

• Octal: Octonary number system, each bit up to 7, up to 8

• Hex: hexadecimal, each with a maximum of the15 or0xf 0xf, less than 16 (that's 0xG0xG,:-D).

Inference:

• If a number is 25, then its binary is not less than 6 binary;

• Naturally it can also be understood that if a number of a certain bit of the value range is[0,m? 1] [0,m?1], then the number is m-m in the system;

>>> 0b101010             # 也即python原生语法是支持二进制表示>> 0xff255 # 自然也支持八进制

Convert to Decimal

int(string, base)            # 第一个参数标识：需要转换的原始的数据，以字符串的形式表示            # 第二个参数标识：原始数据的base或者叫本身的进制表示 # 2：二进制 # 8：八进制 # 16：表示16进制 # 最终转化为十进制

Binary? Decimal

int(‘1010‘, 2)10

Hexadecimal? Decimal

int(‘f‘, 16)15>>> int(‘0xf‘, 16)15>>> int(‘0xff‘, 16)255

Octal? Decimal

int(‘17‘, 8)15              # 15 = 7*8^0+1*8^1

Convert to 16 binary

hex(string)            # 也即没有进制的设置            # 只接受10进制            # 为实现其他进制的转换，可先转换为十进制使用int()            # 返回位字符串类型

hex(1033)‘0x409‘>>> hex(int(‘101010‘, 2))‘0x2a‘>>> hex(int(‘17‘, 8))‘0xf‘

Convert to Binary

bin(十进制整型)

>>> bin(10)‘0b1010‘>>> bin(int(‘ff‘,16))‘0b11111111‘>>> bin(int(‘17‘,8))‘0b1111‘

Convert to Octal

oct()            # 不同于hex/bin            # 通过参数进行判断            # 其是二进制、十进制、16进制            # 也即oct函数可将任意进制的数转换为8进制

>>> oct(0b1010)‘012‘>>> oct(11)‘013‘>>> oct(0xf)‘017‘

To m进制The conversion

Constant to the m modulus of redundancy, the remainder of the current position (low to high), the new dividend, the support quotient of 0.

example, we convert from 25 to 3 in decimal;

25/3? 8 (1)
8/3? 2 (2)
2/3? 0 (2)

Then 25 of the three-binary is represented as221，1 3 0+2 3 1+2 3 2=25 1?30+2?31+2?32=25

def base(x, m):    ms = []    while x: ms.append(x%m) x //= m # python 3 # //：表示整除，保留整数部分 // /：得float类型 return ms

Python data structure: conversion exploration