Python in a shallow copy of the list of deep copy of the alternative understanding of the way

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Created by: Xu Yang
Created: June 13, 2017 22:25:23
Code Features: Detailed analysis list of shallow copy and deep copy
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#导入copy模块
Import Copy
List1 = [1,2,3,["A", "B", "C"]]
#对表1进行浅复制
List2 = Copy.deepcopy (list1) #copy. Copy
#查询表1中各个元素的内存地址
Address0 = ID (list1[0])
Address1 = ID (list1[1])
Address2 = ID (list1[2])
ADDRESS3 = ID (list1[3])
ADDRESS30 = ID (list1[3][0])
ADDRESS31 = ID (list1[3][1])
Address32 = ID (list1[3][2])
#查询表2中各个元素的内存地址
Address_0 = ID (list2[0])
Address_1 = ID (list2[1])
address_2 = ID (list2[2])
Address_3 = ID (list2[3])
address_30 = ID (list2[3][0])
address_31 = ID (list2[3][1])
address_32 = ID (list2[3][2])
# Print out the memory address of table 1 and the memory address of List 2
Print ("---------first comparison---------")
Print ("Listing 1:", ADDRESS0,ADDRESS1,ADDRESS2,ADDRESS3,ADDRESS30,ADDRESS31,ADDRESS32)
Print ("Listing 2:", address_0,address_1,address_2,address_3,address_30,address_31,address_32)
# Modify a value in List 1
List1[1]=-1
#查询表1中各个元素的内存地址
Address0 = ID (list1[0])
Address1 = ID (list1[1])
Address2 = ID (list1[2])
ADDRESS3 = ID (list1[3])
ADDRESS30 = ID (list1[3][0])
ADDRESS31 = ID (list1[3][1])
Address32 = ID (list1[3][2])
#查询表2中各个元素的内存地址
Address_0 = ID (list2[0])
Address_1 = ID (list2[1])
address_2 = ID (list2[2])
Address_3 = ID (list2[3])
address_30 = ID (list2[3][0])
address_31 = ID (list2[3][1])
address_32 = ID (list2[3][2])
# Print the memory address of this list 1 and the memory address of List 2
Print ("---------second comparison---------")
Print ("Listing 1:", ADDRESS0,ADDRESS1,ADDRESS2,ADDRESS3,ADDRESS30,ADDRESS31,ADDRESS32)
Print ("Listing 2:", address_0,address_1,address_2,address_3,address_30,address_31,address_32)
Print (LIST1,LIST2)
# Modify the value in the third element in list 1
LIST1[3][1] = 6
#查询表1中各个元素的内存地址
Address0 = ID (list1[0])
Address1 = ID (list1[1])
Address2 = ID (list1[2])
ADDRESS3 = ID (list1[3])
ADDRESS30 = ID (list1[3][0])
ADDRESS31 = ID (list1[3][1])
Address32 = ID (list1[3][2])
#查询表2中各个元素的内存地址
Address_0 = ID (list2[0])
Address_1 = ID (list2[1])
address_2 = ID (list2[2])
Address_3 = ID (list2[3])
address_30 = ID (list2[3][0])
address_31 = ID (list2[3][1])
address_32 = ID (list2[3][2])
# Print the memory address of this list 1 and the memory address of List 2
Print ("---------third comparison---------")
Print ("Listing 1:", ADDRESS0,ADDRESS1,ADDRESS2,ADDRESS3,ADDRESS30,ADDRESS31,ADDRESS32)
Print ("Listing 2:", address_0,address_1,address_2,address_3,address_30,address_31,address_32)
# cause Analysis: Look at the picture
Print (LIST1,LIST2)

Python in a shallow copy of the list of deep copy of the alternative understanding of the way