Python Learning Essay 1

In a list, find the location of the repeating array.

For example, in the list name = [1, 5, 8, 22, 56, 2, 8, 45, 7, 2, 35, 2, 486, 2, 152, 111, 265, 2, 2], locate the 2 position.

Method 1:

The process is:

Find the first 2 position, then slice after a number after 2, then look for 2, then the next number of slices, loop down.

The first 2 position is the first 2 position in name.

The position of the second 2 is the position of the first 2 plus the 2 position in the second slice plus 1 (position starting from 0)

The third and so on.

Code:

#_*_coding:utf-8_*_name= [1, 5, 8, 22, 56, 2, 8, 45, 7, 2, 35, 2, 486, 2, 152, 111, 265, 2, 2]new_pos= 0#initial position Positioning 0 forIinchRange (Name.count (2)):#number of occurrences for the For loop number 2New_list = Name[new_pos:]#slices, from the first 0 slices, implement new_list = nameNext_pos = New_list.index (2)#the first 2 position to find    PrintNext_pos + New_pos#position of output 2, plus next position from new positionNew_pos + = Next_pos + 1#The new position adds one to the next position, because the slice starts at a number after 2, or the next 2 position is permanently 0

Output Result:

Method 2 (Hyper-violence):

The process is:

Starting from the first 2, each time the position of 2 is deleted, the next 2 of the position plus the number of deleted 2.

The code is as follows:

# _*_coding:utf-8_*_  = [1, 5, 8, 8, 2, 7,, 2, 2,, 2, 486, 2,, 2]for in# Number of cycles as 2 occurrences in the list    Print # The position of the output 2 plus the number of I, I is 0, 1, 2, 3 ... Just delete the number of times 2    del#  Delete the current output of 2, form a new list into the next loop

Output Result:

Python Learning Essay 1