Python learning list of Guibs

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# List # A list consists of a series of elements arranged in a specific order. the elements and elements can have no relationship. # In Python, square brackets [] are used to represent the list and comma is used, to separate the elements, ages = ['swift ', "python", "objective-C"] print (AGES) # access list elements # The list is an ordered set, therefore, to access any element in the list, you only need to tell Python the location or index of the element. # In Python, the index of the first element is 0 print (ages [0]). print (ages [1]) print (ages [2]) # When the list is not empty: # set the index to-1, you can return the last element print (ages [-1]) in the Python list # set the index to-2. you can return the second-to-last element print (ages [-2) in the Python list. ]) # Set the index to-3. you can return print (ages [-3]), the last and third element in the Python list. # use the element wanna_use = "I 'd like to use" + ages [1] in the list. title () + ". "print (wanna_use) # add, modify, and delete elements # modify the list element motorcycles = ['Honda', 'yamaha', 'suzuki'] print (motorcycles) motorcycles [0] = 'ducata' print (motorcycles) # Add list elements # add at the end of the list #[. append ()] motorcycles. append ('yamaha') print (motorcycles) # insert an element in the list #[. insert ()] motorcycles. insert (1, "hl") print (mot Orcycles) # delete a list element # [del] print (motorcycles) del motorcycles [1] print (motorcycles) # delete a specified element and return the deleted value #[. pop ()] poped_motor = motorcycles. pop (0) print (poped_motor) # Delete an element by value #[. remove ()] # only print (motorcycles) motorcycles, the first element that matches the value, will be deleted. remove ('yamaha') print (motorcycles) # organization list # sort the list permanently #[. sort ()] cars = ['BMW ', 'Audi', 'Toyota ', 'mini'] print (cars) cars. sort () print (cars) # flashback cars. sort (reverse = True) print (cars )# Use the sorted () list for temporary sorting. cars2 = ['BMW ', 'Audi', 'Toyota ', 'mini'] print (cars2) print (sorted (cars2 )) print (cars2) # reverse print (sorted (cars2, reverse = True) # permanently reverse the list order #[. reverse ()] foods = ['apple', 'pear ', 'banana'] print (foods) foods. reverse () print (foods) # determine the length of the list # [len ()] print (len (foods) # When using the list, avoid index errors # operation List # traverse the entire list magicians = ['Alice ', 'David', 'privacy lina'] for magician in magicians: print (magician. title () +", That was a great trick! ") Print (" I can't wait to see your next trick \ n ") print (" Thank you everyone ") # Create a value list # generate a series of numbers # [range ()] for value in range (1, 5): print (value) #1, 2, 3, 4 # specify the step for value in range (1, 5, 2): print (value) #1 3 # use the function list () to convert range () the result is converted to the list numbers = list (range (1, 6) print (numbers) # number list processing numbers = [1, 3, 2, 7, 4, 5, 6] print (max (numbers) # maximum value print (min (numbers) # minimum value print (sum (numbers )) # summation # List parsing squares = [value ** 2 for value in range (1, 10)] print (squares) # use part of the list # Slice [to create a slice, you can specify the index of the first and last elements to be used + 1] computers = ['MacBook ', 'MacBook Pro', 'imac ', 'Mac Pro'] print (computers []) # obtain the print (computers [1:]) element of 1 <= index <2) # obtain 1 <= index element print (computers [: 2]) # obtain index <2 element print (computers [:-1]) # obtain the print (computers [-3:]) element before the last element # obtain the last three elements # traverse the slice for computer in computers []: print (computer. upper () # copy the list # Create a shard wanna_food = ['apple', 'pear ', 'banana'] print (wanna_food) that omits the index restriction) buy_food = wanna_food [:] print (buy_food) # if slice is not used. directly assigning the old list to the new array is equivalent to directly referencing the same list, rather than copying copies.

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