Python Login Validator

Name:LoginAuth.py

Fuctions: Login authentication, hidden input password, the same user 3 times input wrong password lock the account, if the user name is Yooma password is yooma login success Prompt Welcome

Code

#!/usr/bin/env python3#auther:yooma 2016-08-15 15:00import sysimport getpassc =  1uname = []while 1:    username = input ("Input  Username: ")     password = getpass.getpass (" Input password: ")      lockfile = open (' Lock.txt ', ' R ')     try:         if username == lockfile.read ():             print ("%s user locked.")  % username)             sys.exit (0)     finally:        lockfile.close ()      if username ==  ' Yooma '  and password ==  ' Yooma ':         print ("welcome %s login success!"  % username)         break    elif  username !=  ' Yooma '  or password !=  ' Yooma ':         print ("Username or password failed,please input again:")          uname.insert (C,username)         s  = set (uname)         for i in s:            if c < 4 and uname.count (i)  == 3:                Lockfile = open (' Lock.txt ', ' W ')                 try:                     lockfile.write (username)                 finally:                    lockfile.close ()                     print ("your account is locked.")                     sys.exit (0)            elif c == 3:                print ("Input  Error 3 times,go out. ")                sys.exit (0)          c+=1        continue &Nbsp;  else:        print ("Input error.")         break

This article is from the "Yooma Technology blog" blog, please be sure to keep this source http://yooma.blog.51cto.com/6965726/1838666

Python Login Validator