Python self-taught lambda expression

For some Python functions, sometimes we only use one or two times in very few cases, but we need to name the function names when we define them, and we can simplify the code by using lambda without having to consider naming problems.
Example:
The following function calculates twice times the X

>> def doublex (x):
Return 2 * x

>> DoubleX (5)
10
>>
is to use lambda to become
>> g = Lambda x:2 * x//LAMBDA followed by parameter name, colon followed by return value
>> g (5)
10
>>

Two examples of parameters comparison

>> def add (x, y):
return x + y

>> Add (3,4)
7
>> g = lambda x,y:x + y
>> g (3,4)
7
>>

See again for example
Filter (), the function has two parameters, the first one is none or another function, the second is a list, the effect is to put each value in the second argument list in the function of the first argument to evaluate the result, all the results of the value of true into a new list, such as:

>> List (filter (none,[1,0,false,true))
[1, True]//[1,0,false,true] in each value, because the first parameter is none, just look at the first and fourth to true, return the list of two values
>>

Example: Returns an odd number in the list, such as range (10)
The General:

>> def Odd (x):
return x% 2

>> temp = range (10)
>> Show = Filter (odd,temp)
>> list (show)
[1, 3, 5, 7, 9]
Using lambda
>> List (filter (lambda x:x% 2,range (10)))
[1, 3, 5, 7, 9]
>>

Python self-taught lambda expression