Python Two-list difference set, set and intersection implementation code _python

Source: Internet
Author: User

① difference Set
Method One:

if __name__ = = ' __main__ ':
	a_list = [{' A ': 1}, {' B ': 2}, {' C ': 3}, {' d ': 4}, {' E ': 5}]
	b_list = [{' A ': 1}], { ' B ': 2}]
	ret_list = [] for
	item in A_list:
		If Item is not in B_list:
			ret_list.append (item) for
	item in B _list:
		If Item not in A_list:
			ret_list.append (item)
	Print (ret_list)

Execution results:

Method Two:

if __name__ = = ' __main__ ':
	a_list = [{' A ': 1}, {' B ': 2}, {' C ': 3}, {' d ': 4}, {' E ': 5}]
	b_list = [{' A ': 1}], {' B ': 2}]
	Ret_list = [item for item in A_list If item is not in B_list] + [item to item in B_list if item not in A_list]
	print (re T_list)

Execution results:

Method Three:

if __name__ = = ' __main__ ':
	a_list = [1, 2, 3, 4, 5]
	b_list = [1, 4, 5]
	ret_list = List (set (A_list) ^set (b_list) )
	Print (ret_list)

Execution results:

Note: In this method, the elements in the two list cannot be dictionaries

② and set

if __name__ = = ' __main__ ':
	a_list = [1, 2, 3, 4, 5]
	b_list = [1, 4, 5]
	ret_list = List (set (A_list). Union (set (b) _list)))
	print (ret_list)

Execution results:

Note: In this method, the elements in the two list cannot be dictionaries

③ intersection

if __name__ = = ' __main__ ':
	a_list = [1, 2, 3, 4, 5]
	b_list = [1, 4, 5]
	ret_list = List (set (A_list). Union (S ET (b_list))) ^ (Set (A_list) ^set (b_list))
	print (ret_list)

Execution results:

Note: In this method, the elements in the two list cannot be dictionaries

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