Python: Writing the Login Interface (Day 1)

Job Requirements:

1. Enter user name, password
2. Authentication successful Display Welcome message
3. Lock user after entering error three times

Readme

1.user_id.txt is the file that holds the user ID and password

2.user_lock.txt is the document that holds the locked user ID, which is empty by default.

3. The program will judge the legal user ID in User_id.txt, if the user ID error is entered three times, the program exits directly.

4. The program will enter the correct user name after the password to judge, enter the password has 3 opportunities, three consecutive errors will lock the user ID and exit.

Flow chart:

Code:

#!/user/binenv python3#-*-coding:utf-8-*-"Created on:2015 year January 16 @author: yi Lv Email: [Email protected]version:                                                  1.0Description: Enter the user name password, authentication successful display welcome information, authentication failed, the wrong three times after the lock "' Import sys,os,getpassos.system (' Clear ') #把终端代码页面清空, provide a clean vision i = 0while i < 3: #只要用户登录异常不 OVER 3 cycles username = input ("Please enter user name:") lock_file = open (' User_lock.txt ', ' r+ ') #当用户输入用户名后, open L                                     Ock file to check if this user is already lock lock_list = Lock_file.readlines () for lock_line in Lock_list:                                   #循环LOCK文件 lock_line = Lock_line.strip (' \ n ') #去掉换行符 if username = = Lock_line: #如果LOCK了就直接退出 sys.exit (' =======warning: The account%s has been frozen ======== '% username) u Ser_file = open (' User_id.txt ', ' R ') #打开帐号文件 user_list = User_file.readlines () for User_li            NE in user_list:                         #对帐号文件进行遍历 (User,password) = User_line.strip (' \ n '). Split () #分别获取帐号和密码信息                                            If username = = User: #如用户名正常匹配 m = 0 while M < 3: #只要用户密码异常不超过3次就不断循环 passwd = getpass.getpass (' Please enter password: ') #输入 Password, relative security if passwd = = password: #密码正确, prompt Welcome login print (' hi,%s, welcome                    Login system '% username ' sys.exit (0) #正常退出 else: if M! = 2: #m = 2 o'clock, is the last chance to have 0 more chances left in the prompt print (' User%s secret Code error, please re-enter, there is%d chance '% (username,2-m)) m + = 1 #密码输入错误后, the loop value is increased                1 else:lock_file.write (username + ' \ n ') #密码输入三次错误后, append the user to the lock file Sys.exit (' User%s ' reaches maximumLogin number, please contact admin!! '% username) Else:pass #当用户没匹配时, Skip and continue to follow Ring Else:if I! = 2: #i = 2 o'clock, is the last chance, no more than 0 chances left in the hint print (' User%s does not exist, please re-enter and%d chance '% (username,2-i)) i + = 1 #当用户输入                                                   Error, loop value increases 1else:sys.exit (' user%s does not exist, exits '% username) #用户输入三次错误后, exception exits Lock_file.close () #关闭lock文件user_file. Close () #关闭 user_id file

　　

Python: Writing the Login Interface (Day 1)