Question one hundred and seventeen: Arrangement

[Plain] Description
 
There are four numbers that are different from each other, and the output is composed of three numbers that are not repeated.
 
Input
 
Four integers are arranged in ascending order.
 
Output
 
Output all arrays. The output format is shown in the example.
 
Sample Input
 
 
1 2 3 4
 
Sample Output
 
 
1 2 3
1 3 2
2 1 3
2 3 1
3 1 2
3 2 1
1 2 4
1 4 2
2 1 4
2 4 1
4 1 2
4 2 1
1 3 4
1 4 3
3 1 4
3 4 1
4 1 3
4 3 1
2 3 4
2 4 3
3 2 4
3 4 2
4 2 3
4 3 2

Description

There are four numbers that are different from each other, and the output is composed of three numbers that are not repeated.

Input

Four integers are arranged in ascending order.

Output

Output all arrays. The output format is shown in the example.

Sample Input

1 2 3 4

Sample Output

1 2 3
1 3 2
2 1 3
2 3 1
3 1 2
3 2 1
1 2 4
1 4 2
2 1 4
2 4 1
4 1 2
4 2 1
1 3 4
1 4 3
3 1 4
3 4 1
4 1 3
4 3 1
2 3 4
2 4 3
3 2 4
3 4 2
4 2 3
4 3 2
 

[Plain] # include <stdio. h>
 
Int main ()
{
Int I;
Int j;
Int k;
Int num [4];
 
For (I = 0; I <4; I ++)
{
Scanf ("% d", & num [I]);
}
 
For (I = 0; I <4; I ++)
{
For (j = 0; j <4; j ++)
{
For (k = 0; k <4; k ++)
{
If (I! = J & I! = K & j! = K & I! = 3 & j! = 3 & k! = 3)
{
Printf ("% d \ n", num [I], num [j], num [k]);
}
}
}
}

For (I = 0; I <4; I ++)
{
For (j = 0; j <4; j ++)
{
For (k = 0; k <4; k ++)
{
If (I! = J & I! = K & j! = K & I! = 2 & j! = 2 & k! = 2)
{
Printf ("% d \ n", num [I], num [j], num [k]);
}
}
}
}
 
For (I = 0; I <4; I ++)
{
For (j = 0; j <4; j ++)
{
For (k = 0; k <4; k ++)
{
If (I! = J & I! = K & j! = K & I! = 1 & j! = 1 & k! = 1)
{
Printf ("% d \ n", num [I], num [j], num [k]);
}
}
}
}
 
For (I = 0; I <4; I ++)
{
For (j = 0; j <4; j ++)
{
For (k = 0; k <4; k ++)
{
If (I! = J & I! = K & j! = K & I! = 0 & j! = 0 & k! = 0)
{
Printf ("% d \ n", num [I], num [j], num [k]);
}
}
}
}
 
Return 0;
}

# Include <stdio. h>

Int main ()
{
Int I;
Int j;
Int k;
Int num [4];

For (I = 0; I <4; I ++)
{
Scanf ("% d", & num [I]);
}

For (I = 0; I <4; I ++)
{
For (j = 0; j <4; j ++)
{
For (k = 0; k <4; k ++)
{
If (I! = J & I! = K & j! = K & I! = 3 & j! = 3 & k! = 3)
{
Printf ("% d \ n", num [I], num [j], num [k]);
}
}
}
}

For (I = 0; I <4; I ++)
{
For (j = 0; j <4; j ++)
{
For (k = 0; k <4; k ++)
{
If (I! = J & I! = K & j! = K & I! = 2 & j! = 2 & k! = 2)
{
Printf ("% d \ n", num [I], num [j], num [k]);
}
}
}
}

For (I = 0; I <4; I ++)
{
For (j = 0; j <4; j ++)
{
For (k = 0; k <4; k ++)
{
If (I! = J & I! = K & j! = K & I! = 1 & j! = 1 & k! = 1)
{
Printf ("% d \ n", num [I], num [j], num [k]);
}
}
}
}

For (I = 0; I <4; I ++)
{
For (j = 0; j <4; j ++)
{
For (k = 0; k <4; k ++)
{
If (I! = J & I! = K & j! = K & I! = 0 & j! = 0 & k! = 0)
{
Printf ("% d \ n", num [I], num [j], num [k]);
}
}
}
}

Return 0;
}