"Linux Learning" writes a daemon

Source: Internet
Author: User

Topic:

Write a daemon that will output the current time every 3 seconds.
Requirements:

You cannot use the Init_daemon system call.

#include <stdio.h>#include<unistd.h>#include<stdlib.h>#include<time.h>#include<unistd.h>intMainvoid) {pid_t pid; PID=Fork (); if(PID >0) {exit (0); }        if(0==pid)                {Setsid ();              time_t now; structTM *TimeNow;  while(1) {Time (&Now ); TimeNow= LocalTime (&Now ); printf ("localtime is:%s\n", Asctime (TimeNow)); Sleep (3); }            }        return 0;}

"Linux Learning" writes a daemon

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