"Pass-through" and "pass-through" learning notes for PHP custom functions

The transfer of parameters can be divided into two types of transmission value and address, what is the difference?

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function fun($num1,$num2){$num1=100;$num2=1000;}$n1=1;$n2=10;fun($n1,$n2);echo “n1={$n1} n2={$n2}”;?>

The result is: N1=1 n2=10

This section of code is the process of passing values, custom function fun parameters pass specific $n1, $n 2 value, this is easy to understand, I said before the custom function is a value, then what is the address?

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function fun($num1,&$num2){$num1=100;$num2=1000;}$n1=1;$n2=10;fun($n1,$n2);echo “n1={$n1} n2={$n2}”;?>

This code, N1 is still the value of the pass, and N2 is the address. What difference does it have? That's right.. is in the function of the parameters of a "&" take the address, meaning is to pass the memory address to the parameter, which is equal to $num2=& $n 2, the result is n3=1 n4=1000.

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"Pass-through" and "pass-through" learning notes for PHP custom functions