# "Leetcode-Interview algorithm classic-java Implementation" "083-remove Duplicates from Sorted list (to remove duplicate nodes in a sorted single-linked list)"

Source: Internet
Author: User

"083-remove duplicates from Sorted list (to remove duplicate nodes in a sorted single-linked list)" "leetcode-Interview algorithm classic-java Implementation" "All topics Directory Index" Original Question

Given a sorted linked list, delete all duplicates such this each element appear only once.
For example,
Given `1->1->2` , return `1->2` .
Given `1->1->2->3->3` , return `1->2->3` .

Main Topic

Given a single linked list, delete the duplicate elements and keep only one.

Thinking of solving problems

Use a pointer to the head of the list, and if the next is equal to the current node, delete until a different one is encountered, and the pointer points to the new node, repeating the operation until all the nodes have finished processing.

Code Implementation

Node class

``publicclass ListNode {    int val;    ListNode next;    ListNode(int x) {        val = x;        null;    }}``

Algorithm implementation class

`` Public classSolution { PublicListNodedeleteduplicates(ListNode head)        {ListNode point; ListNode tail = head;//point to the end of the new node, start the chain with only one element, that is, the chain head        if(Head! =NULL) {point = Head.next;//point to the head of the other chain             while(Point! =NULL) {//The other chain is not yet at the end                if(Tail.val! = point.val) {//If it is not the same as the tail node, link the different nodes to the next location of tailTail.next = point; tail = Tail.next;//re-pointing the end of the chain} point = Point.next; } Tail.next =NULL;//chain tail pointing to null}returnHead }}``
Evaluation Results

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"Leetcode-Interview algorithm classic-java Implementation" "083-remove Duplicates from Sorted list (to remove duplicate nodes in a sorted single-linked list)"

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