[Seemingly challenging] How does shell get the return value in php?-php Tutorial

[Seemingly challenging] How does shell obtain the return value in php? for example, the php file returns an array & nbsp; PHPcode & lt ;? Phpreturnarray (a & gt; 1, B & gt; 2, c & gt; public, d & gt;, e & gt ;,);? & Gt; in she [seemingly challenging] How does shell get the return value in php?
The php file returns an array.

PHP code

  
   '1',  'b' => '2',  'c' => 'public',  'd' => '',  'e' => '',);?>

How can I receive this array in shell?

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PHP code

[User: root Time: 07: 23: 08 Path:/home/liangdong/php] $ php. php Array ([a] => 1 [B] => 2 [c] => public [d] => [e] =>) [User: root Time: 07: 23: 10 Path:/home/liangdong/php] $ cat. php
  [User: root Time: 07: 23: 12 Path:/home/liangdong/php] $ cat B. php
  '1', 'B' => '2', 'C' => 'public', 'D' => '', 'E' => '',);?>
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Shell is not familiar with it. I guess I will use it later, so I studied one,


  
  

   
   
PHP code
   
   
#! /Bin/basheval 'cat php_data.txt | grep "=>" | tr-d ",> \ '" | xargs-I {} echo {}\; | tr "\ n" 'echo $ {a} echo $ {B} echo $ {c} echo $ {d}
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Cross-language data exchange requires a data structure that can be identified by both parties,
Otherwise it will be meaningless.

If your sample php code has been pre-compiled by zend, or is blocked by Wei shield (you cannot say that it is not a php file)
Then how do you separate the data in shell?