Shell scripts recursively Extract files from folders,

Source: Internet
Author: User

Shell scripts recursively Extract files from folders,
Requirement

Two days ago, I ran into the need to extract files from a folder around 10 layers, so I wrote this script.

The file structure is as follows:

    dir1    ├── a    │   ├── b    │   │   └── file1    │   └── file2    ├── c    │   └── d    │       ├── e    │       │   └── file4    │       └── file3    └── file5

We need ~ File5 is extracted and put into another folder.

Script

The script getfilefromdir. sh is as follows:

#! /Bin/bash # desc: get file from directory # author: a decade later, Lu brother (http://www.cnblogs.com/lurenjiashuo/) # example: sh getfilefromdir. sh A BINIT_PATH =$ {1%/} SAVE_PATH =$ {2%/} function checksavepath () {if [-d $ SAVE_PATH] then rm-rf $ SAVE_PATH fi mkdir $ {SAVE_PATH} touch $ SAVE_PATH ". log "} function getfilefromdir () {for file in 'ls $ 1' do if [-d $1 #/" $ file] then getfilefromdir $1 #/" $ file else local path = "$1/$ fi Le "local name = $ file if [! -F $ SAVE_PATH "/" $ name] then echo "cp $ {path} to $ {SAVE_PATH}/$ {name}" cp $ {path} "$ {SAVE_PATH }/ $ {name} "else echo" $ {path} file already exists "echo" $ {path} ">>$ SAVE_PATH ". log "2> & 1 fi done} checksavepathfor sfol in $ {INIT_PATH} do getfilefromdir $ {sfol} done
Run
sh getfilefromdir.sh dir1/ dir2

The first parameter is the source folder, and the second parameter is the destination folder (you do not need to create it in advance ).

If a file with the same name exists, it will exist in dir2.log.

Result:

dir2├── file1├── file2├── file3├── file4└── file5

This article from ten years later brother Lu blog (http://www.cnblogs.com/lurenjiashuo/), reprint please indicate the original address.

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