This article describes the simple implementation of a Python single-chain table, including defining required fields and analyzing specific implementation code, for more information about how to implement a Python single-chain table, see the following example. The specific method is as follows:
Generally, to define a single-chain table, first define the linked list Element: Element. It contains three fields:
List: indicates which list you belong.
Datum: change the value of an element.
Next: location of the next node
The specific implementation code is as follows:
class LinkedList(object): class Element(object): def __init__(self,list,datum,next): self._list = list self._datum = datum self._next = next def getDatum(self): return self._datum datum = property( fget = lambda self: self.getDatum()) def getNext(self): return self._next next = property( fget = lambda self: self.getNext()) def __init__(self): self._head = None self._tail = None def getHead(self): return self._head head = property( fget = lambda self: self.getHead()) def prepend(self,item): tmp = self.Element (self,item,self._head) if self._head is None: self._tail = tmp self._head = tmp def insert(self, pos, item): i = 0 p = self._head while p != None and i < pos -1: p = p._next i += 1 if p == None or i > pos-1: return -1 tmp = self.Element(self, item, p._next) p._next = tmp return 1 def getItem(self, pos): i = 0 p = self._head while p != None and i < pos -1: p = p._next i += 1 if p == None or i > post-1: return -1 return p._datum def delete(self, pos): i = 0 p = self._head while p != None and i < pos -1: p = p._next i += 1 if p == None or i > post-1: return -1 q = p._next p._nex = q._next datum = p._datum return datum def setItem(self, pos, item): i = 0 p = self._head while p != None and i < pos -1: p = p._next i += 1 if p == None or i > post-1: return -1 p._datum = item return 1 def find(self, pos, item): i = 0 p = self._head while p != None and i < pos -1: if p._datum == item: return 1 p = p._next i += 1 return -1 def empty(self): if self._head == None: return 1 return 0 def size(self): i = 0 p = self._head while p != None and i < pos -1: p = p._next i += 1 return i def clear(self): self._head = None self._tail = Nonetest = LinkedList()test.prepend('test0')print test.insert(1, 'test')print test.head.datumprint test.head.next.datum
I hope this article will help you with Python programming.