SQL Server Starter Statement summary _mssql

For a database to have more or less to master, the first basic SQL statements to understand. Here's a summary of some entry-level SQL statements.

Create related

Show Database; Show the existing database
use database_x; Now you want to use the database database_x
CREATE TABLE coffee (id int (5) Not null,coffee_name varchar (25)); Create a table that contains IDs and coffee_name two fields
ALTER TABLE coffee add taste varchar (10); Add a new column
insert into coffee (Id,coffee_name,taste,rank) value ("1", "BlueMountain", "OK", "5"); Inserting data
show columns from coffee; View table Structure
Show create TABLE coffee; View table information, including the build table statement
ALTER TABLE student rename SS; Change table name
ALTER TABLE SS drop Mark; Delete Mark column in table SS
SELECT statement

select * from coffee where id= "1"; query out all id=1 information
Select Coffee_name from coffee where id= "2"; query out id=2 coffee name SELECT * FROM club where ID between "1" and "3"; Query for entries from id=1 to 3
select * FROM club where id= "1" or id= "3"; query out id=1 and id=3 two entries
select Club_name from club where Mark> ; 50; Check out the club with Mark greater than 50
select Club_name from the club where Mark not between  and 50; check mark is not in the club between 48 and 50
SELECT * From club where ID in ("1", "3", "4"); Query id=1,3,4 Entries
select * FROM club where ID is not in ("1", "3", "4");
SELECT * from the club where name like "m%r"; Wildcard% represents characters of any length (can be 0, Chinese characters are two characters)
select * FROM club where name like "M_r"; _ Represents a single character
select * FROM club where ID in ("1", " 3 "," 4 ") and mark>50; Multiple Queries
SELECT * FROM club orders by Mark Desc, in descending order of Mark (desc: Descending, USC: Ascending)
Quantity query related

Select COUNT (*) from club; Find out how many records are in the club
Select COUNT (distinct mark) from club; How many records are there in different fractions?
select SUM (Mark) from club; Sum of points
Select AVG (Mark) from club; Average integral
select Max (Mark) from club; Maximum integral
Select min (Mark) from club; Minimum integral
UPDATE statement

Update Club set mark=mark-8 where id= "1"; Id=1 's club is fined 8 points.
Delete statement

Delete from club where id= "001"; Delete Id=001 's Club information
The above statements are SQL statements and additions to check the most basic part of the entry level, must be mastered.