Squared sum of squares---Python

Source: Internet
Author: User

The sum of squares of the first 10 natural numbers is:
1^2 + 2^2 + ... + 10^2 = 385
The sum of their squares is:
(1 + 2 + ... + 10) ^2 = 55^2 = 3025
So, the sum of squares of the first 10 natural numbers and the squared difference 3025-385=2640
So, what is the sum of the squares of the first 100 natural numbers and the squared difference?

Result1=0
Result2=0
For I in Range (1,101):
Result1=result1+i*i
For I in Range (1,101):
Result2=result2+i
Result2=result2*result2
Result=result2-result1
Print (Result)

Squared sum of squares---Python

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