String similarity (implemented in java)

Source: Internet
Author: User
Public class test {/*** we define the similarity between two strings as the cost of converting a string into another string (the conversion method may not be unique ), the higher the conversion cost, the lower the similarity between the two strings. For example, two strings: "SNOWY" and "SUNNY". Below are two methods to convert "SNOWY" to "SUNNY": 1: s-n o w y s u n-Y Cost = 3 (insert U, replace O, delete W) transform 2: -s n o w-y s u n-n y Cost = 5 (insert S, replace S, delete O, delete W, insert N) use d [I, j] indicates source [1 .. i] to target [1 .. if the source [I] is equal to target [j], then the recursive relationship of d [I, j] can be calculated as follows: d [I, j] = d [I, j] + 0 (recurrence 1) If source [I] is not equal to target [j], based on the insert, delete, and replace policies, the distance between the three policies is calculated, and the smallest one is: d [I, j] = min (d [I, j, j-1] + 1, d [I-1, j] + 1, d [I-1, j-1] + 1) (recursive formula 2) d [I, j-1] + 1 indicates that the minimum editing distance d [I-1, j] + 1 indicates that the minimum editing distance d [I-1, j-1] + 1 indicates replacing source [I] with target [I], and then calculating the minimum editing distance * @ param args */public static void main (String [] args) {// TODO Auto-generated method stubString source = "SUNNY"; String target = "hgjdSUN"; int I = 0; // I = EditDistanceChange (source, target ); I = EditDistance (source, target); System. out. Println ("requires" + I + "times");} // Dynamic Programming private static int EditDistance (String source, String target) {char [] s = source. toCharArray (); char [] t = target. toCharArray (); int slen = source. length (); int tlen = target. length (); int d [] [] = new int [slen + 1] [tlen + 1]; for (int I = 0; I <= slen; I ++) {d [I] [0] = I;} for (int I = 0; I <= tlen; I ++) {d [0] [I] = I ;} for (int I = 1; I <= slen; I ++) {for (int j = 1; j <= tlen; j ++) {if (s [I-1] = t [J-1]) {d [I] [j] = d [I-1] [J-1];} els E {int insert = d [I] [J-1] + 1; int del = d [I-1] [j] + 1; int update = d [I-1] [J-1] + 1; d [I] [j] = Math. min (insert, del)> Math. min (del, update )? Math. min (del, update): Math. min (insert, del) ;}} return d [slen] [tlen] ;}// Recursive Implementation --- exhaustive method (enumeration method) private static int EditDistanceChange (String source, String target) {if (target. length ()! = 0 & source. length () = 0) {return EditDistanceChange (source, target. substring (1) + 1;} else if (target. length () = 0 & source. length ()! = 0) {return EditDistanceChange (source. substring (1), target) + 1;} else if (target. length ()! = 0 & source. length ()! = 0) {// when the first value of the source character is the same as the first value of the target character if (source. charAt (0) = target. charAt (0) {return EditDistanceChange (source. substring (1), target. substring (1);} else {int insert = EditDistanceChange (source. substring (1), target) + 1; int del = EditDistanceChange (source, target. substring (1) + 1; int update = EditDistanceChange (source. substring (1), target. substring (1) + 1; return Math. min (insert, del)> Math. min (del, update )? Math. min (del, update): Math. min (insert, del) ;}} else {return 0 ;}}}

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