The difference between i++ in Java and i++ in C

In Java:

Using the intermediate variable mechanism:
i = i++;

Equivalent:

temp = i;
i = i + 1;
i = temp; (i.e. i = i++ = temp)

int a = 0,sum;

In Java, after using the expression a++, a immediately adds one;

For sum = a++ + a++;

Java: After the first a++ executes, the value of a is immediately added to 1, and the value of a is 1 before the second a++ executes.

A = 0;
A = a++ + a++;

Temp1 = A; --Temp1 = = 0;
A = a+1; A = a+1;
Temp2 = A; --Temp2 = = 1;
A = a + 1; A = a+1;
A = Temp1 + Temp2; A = Temp1 + Temp2;

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int a = 0, sum;

A = a++;
System.out.println (a);

The result is: 0
-------------------------------------

int a = 0, sum;

sum = a++ + a++;

SYSTEM.OUT.PRINTLN (sum);
System.out.println (a);

The result is: 1 and 2

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int a = 0, sum;

A = a++ + a++;

System.out.println (a);

The result is: 1

--------------------------------------
int a,sum;
A = 0;

sum = a++ + ++a;

SYSTEM.OUT.PRINTLN (sum);
System.out.println (a);

The result is: 2 and 2

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In the C language:

+ + is a unary operator: + and = Both are two-tuple operators

For unary operators, the return value is: i++ is the value of I, ++i is the value of I plus one

The i++ operation means that a self-increment instruction is generated after the instruction of the two-dollar operator is generated (that is, after the "+" and "=" operations have been completed, the increment is added).

The ++i operation means that a self-increment instruction is generated before the instruction generated by the two-dollar operator (that is, it is self-increasing before the "+" and "=" operations are executed).

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int i = 0, sum;

Test unary operators

If printf ("%d", I); The result is: 0

If printf ("%d", i++); The result is: 0

If printf ("%d", ++i); The result is: 1

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int i = 0, sum;

Testing the two-dollar operator

sum = i++;

printf ("%d", sum);
printf ("%d", I);

The result is: 0 and 1

If you change to:

i = i++;
printf ("%d", I);

The result is: 1

----------------------------------------------------------------------

int a = 0, sum;

sum = a++ + a++;

printf ("%d\n", sum);
printf ("%d\n", a);

The result is: 0 and 2

Analysis:

First a++ is executed (at this point, the value of a is 0),

Then execute the second a++ (at which point A has a value of 0),

Finally, the addition and assignment operations are performed (at this point a value of 0,sum is 0 + 0 = 0),

After the addition operation is finished, perform a two plus action (at which point A is 2)

If you change to:

A = a++ + a++;

printf ("%d", a);

The result is: 2

----------------------------------------------------------------------

int a = 0,sum;

A = a++ + ++a;
printf ("%d\n", a);

Process:
First, a self-increment of 1, which is brought by ++a (even if a++ on the far left). At this point a = 1

We then calculate the two operand of the + sign.
Because they are actually a (this involves the compiler implementation problem, most C compilers will combine the two operands, that is, the variable a),
The value is 1, so that the return value of a++ + ++a is 1+1=2, and then the value of a++ + ++a is assigned to a, when a = 2

Finally, complete the self-increment instruction brought by a++, at which point A is the value of 2+1=3, which is a = 3

The result is: 3

If you change to:
sum = a++ + ++a;
printf ("%d", sum);
printf ("%d", a);

Process:
First, a self-increment of 1, which is brought by ++a (even if a++ on the far left). At this point a = 1

Then, we calculate the + number of the two operands.
Because they are actually a (this involves the compiler implementation problem, most C compilers will combine the two operands, that is, the variable a),
The value is 1, so that the return value of a++ + ++a is 1+1=2, and then the value of a++ + ++a is assigned to sum, when sum = 2,a = 1

Finally, complete the self-increment instruction brought by a++, at which point A is the value of 1+1=2, which is a = 2

Results are: 2 and 2

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A = a++ ++a; Differences in Java and C

In Java, a++ is executed first,
C, first execute the ++a



The difference between i++ in Java and i++ in C