The Java implementation reads in a number n, calculates the sum of its numbers, and writes each digit in Hanyu Pinyin.

Source: Internet
Author: User

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The title is "read in a number n, calculate the sum of their numbers, write in Hanyu Pinyin and each digit", is implemented in C language. Since I am currently learning Java, I would like to use Java to achieve the next.

Input format: Each test input contains 1 test cases, which gives the value of the natural number N. This guarantees that n is less than 10100.

Output format: output n in one line each digit of the sum of the number of digits, there are 1 spaces between the phonetic numerals, but there is no space after the last phonetic number in a row.

import java.io.bufferedreader;import java.io.ioexception;import java.io.inputstreamreader; Public class int_to_string {    public static void main ( String[] args)  {        BufferedReader br =  New bufferedreader (New inputstreamreader (system.in));         try {            int sum =  0 ;            string str =  br.readline ();             //resolves a problem that exceeds the int type. The string is assembled by the number of characters.             char[] ch =  Str.tochararray ();            for  (int i  = 0 ; i < ch.length ; i ++)  {                 //sum                  sum +=  new integer ("" +ch[i]). IntValue ();             }             system.out.println (Print_f (sum));         }  catch  (ioexception e)  {             e.printstacktrace ();        } finally {             try {                 if  (br != null)  {        &nbSp;            br.close ();                 }             } catch  (ioexception e)  {                 e.printstacktrace ();             }        }     }        public static string print_f (int sum)  {        int k = 1;         int m = sum;         String str =  "";        while  (m >= &NBSP;10)  {            k *= 10 ;             m /= 10;         }        while (k != 0)  {             str += int_to_string (sum / k) + " ";             sum %= k;             k /= 10;         }        return str.substring (0, str.length ()-1) ;     }    //Conversion     public static string  int_to_string (int n)  {        string ss =   "";         switch  (n)  {        case  0:            ss =  "Ling";             break;         case 1:            ss =   "Yi";            break;         case 2:             ss =  "ER";            break;         case 3:             ss =  "San";             break;        case 4:             ss =  "Si";            break;         case 5:             ss =  "WU";            break;         case 6:             ss =  "Liu";             break;        case 7:             ss =  "Qi";             break;        case 8:             ss =  "BA";             break;        case 9:             ss =  "JIU";             break;        default:             break;         }        return ss;    }}




This article is from the "Orange Growth Record" blog, be sure to keep this source http://azhome.blog.51cto.com/9306775/1546766

The Java implementation reads in a number n, calculates the sum of its numbers, and writes each digit in Hanyu Pinyin.

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