The problem code that determines the size of the directory in PHP

 
                                                                      ($address) Address incoming file path {$size=0;//Initialize file size variable if($dir= @opendir($address))If you open the file normally, do the next step {while($filename=readdir($dir)){if($filename! = "." &&$filename! = "..."){if(Is_file($address.") \\". $filename)){$size+=filesize($address." \\". $filename); } if(Is_dir($address.") \\". $filename)){$size+=directory_size($address." \\". $filename); }}} @closedir($dir); Return$size; }$dire _address="F:\course";$totalsize=directory_size($dire _address); Printf("%s",$totalsize);? >

Description @: Hides the error output by adding "@" to the function name
Opdendir: Open Directory handle
Readdir: Returns an entry in a directory handle opened by Opendir ()
Is_file: Determine if it is a file
Is_dir: Determine if it is a directory

Lab Environment: Windows 10 operating system
Eclipse for PHP Developers (Mars)
Wampserver Version2.4

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The above describes the PHP to determine the size of the relevant problem code, including aspects of the content, I hope that the PHP tutorial interested in a friend helpful.

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