This works too? How can this problem be solved?

This works too? Is the string and 0 of all letters always equal? PHPcodeif (& quot; e & quot ;== 0) {echo & quot; Yes & quot ;;}# result: # Yes, & quot; e & quot; is it true if it is not a variable?
Is the string and 0 of all letters always equal? Explanations

PHP code

  if("e" == 0){    echo "Yes";}#result：#Yes

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"E" is not a variable in the memory. nothing .......
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This way:

PHP code

Echo "e" = 0;
------ Solution --------------------
Php will automatically convert the type of the variable, and convert string to int if int and string are compared. as a result, all strings are 0, and the result is determined, you can use = full to determine
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This solution is clearer:

Echo intval ('e'); # The conversion fails. the default value is 0 (print: 0)
Echo intval ('1ds2e'); # if there is an integer in the string, convert it to int (print: 1) from the first position)


  
   Discussion
   

   
This way: PHP code
   
Echo "e" = 0;
   

  
------ Solution --------------------

This statement is wrong. "If there is an integer in the string, convert it from the first position to int (print: 1 )"

It should be like this:

If an integer appears in a string and the integer is at the starting position of the string, it is taken out and converted to an int.


  
   Discussion
   

   
This solution is clearer:
   

   
Echo intval ('e'); # The conversion fails. the default value is 0 (print: 0)
   
Echo intval ('1ds2e'); # if there is an integer in the string, convert it to int (print: 1) from the first position)
   

   
Reference:
   

   
This way: PHP code
   
Echo "e" = 0;