To find the number of days between two dates, Python implements

The code is as follows

1 defLeap_year (y):#determine if a leap year2     if(y% 4 = = 0 andY% 100 = 0)orY% 400 = =0:3         returnTrue4     Else:5         returnFalse6         7 defDays_in_month (Y, m):#Judging every month for a few days8     ifMinch[1, 3, 5, 7, 8, 10, 12]:9         return31Ten     elifMinch[4, 6, 9, 11]: One         return30 A     Else: -         ifleap_year (y): -             return29 the         Else: -             return28 -              - defDays_this_year (year):#Judging a few days this year +     ifleap_year (year): -         return366 +     Else: A         return365 at              - defDays_passed (year, Month, day):#Judging how many days have gone by this year -m = 1 -Days =0 -      whileM <Month: -Days + =Days_in_month (year, m) inM + = 1 -     returnDays + Day to  + defdaysbetweendates (year1, Month1, Day1, Year2, Month2, day2): -     ## the     #Your code here. *     ## $     ifYear1 = =year2:Panax Notoginseng         returnDays_passed (Year2, Month2, Day2)-days_passed (year1, Month1, Day1) -     Else: theSUM1 =0 +Y1 =year1 A          whileY1 <year2: theSum1 + =days_this_year (y1) +Y1 + = 1 -         returnSum1-days_passed (year1,month1,day1) +days_passed (year2,month2,day2)

Use the following code for correctness testing

defTest (): Test_cases= [((2012,1,1,2012,2,28), 58),                   ((2012,1,1,2012,3,1), 60),                  ((2011,6,30,2012,6,30), 366),                  ((2011,1,1,2012,8,8), 585 ),                  ((1900,1,1,1999,12,31), 36523)]     for(args, answer)inchTest_cases:result= Daysbetweendates (*args)ifResult! =Answer:Print "Test with data:", args,"failed"        Else:            Print "Test Case passed!"Test ()

The test results are as follows