Two ways to count the number of string words (C language Implementation)

Problem Description: Statistics a string, string consisting of words, spaces.

Ideas:

One, traverse all characters of the string, set a Boolean variable to determine whether the current is a space or a letter

　　　　

1#include <stdio.h>2#include <stdbool.h>3#include <string.h>4 5 intCount_words (Char*s)6 {7     intLen=strlen (s);//len holds string length8     BOOLIswhite=true; 9     intI,count=0;//Count is used to count the number of wordsTen      for(i=0; i<len;i++) One     { A         if(* (s+i) = =' ')//the current character is empty -         { -Iswhite=true; the}Else if(Iswhite) {//This code is executed to indicate that the current character is not empty and the last character is empty -count++;//number of words +1 -Iswhite=false;//enter a non-whitespace state -         } +     } -     returncount; + } A  at intMain () - { -     Char* a="I Love you"; -printf"%d", Count_words (a)); -}

　　

Second, traversing all characters of the string, if the current character is not empty, the number of words +1, and then nested a while loop to determine whether the current word is ending

1#include <stdio.h>2#include <string.h>3 4 intCount_words (Char*s)5 {    6     intlen=strlen (s);7     intcount,i;8      for(i=0; i<len;i++)9     {Ten         if(* (s+i)! =' '){//If the current code is empty Onecount++;//number of words +1 A              while(* (s+i)! =' '&& I<len)//determines whether the current word ends -i++; -         } the     } -     returncount; - } -  + intMain () - { +     Char* a="I Love you"; Aprintf"%d", Count_words (a)); at}

Two ways to count the number of string words (C language Implementation)