Use EMGUCV's Imagebox () to open and display a pair of images in C #

1. Add a PictureBox in the toolbox to the interface.

2. Find the definition code for the PictureBox control you just added in the code snippet generated by the Windows window designer XXXXX.Designer.cs:

Modified to:

This allows you to display an image (image, Mat) to the control in the main program through code.

3. Add a TextBox control to display the picture path, and change it to "read-only" in the property.

4. Add a control OpenFileDialog to open the file.

5. Add a button to open the image and add the following code to the calling function:

            DialogResult result = openfiledialog1.showdialog ();             if (Result = = DialogResult.OK | | result = = Dialogresult.yes)            {                = openfiledialog1.filename;            }

The above code OPENFILEDIALOG1 and textBox1 based on actual modifications.

6. Add code to read in and display the image

         Public voidperformshapedetection () {if(TextBox1.Text! = String.Empty)//determine if the address in the text box is empty{StringBuilder Msgbuilder=NewStringBuilder ("Performance:"); //Load the image from file and resize it for displayImage < Bgr,byte> img =NewIMAGE&LT;BGR,byte>(TextBox1.Text). Resize (814,539, Emgu.CV.CvEnum.Inter.Linear,true);//the size of the image is determined by the actual size of the control//Mat srcimg = Cvinvoke.imread (TextBox1.Text);pictureBox1.Image = img;//display image to control                 This. Text =msgbuilder.tostring (); 

7. When the address changes in the Add text box control, the calling code of the image code is displayed.

        Private void textbox1_textchanged (object  sender, EventArgs e)        {            performshapedetection ();        }

 This New System.EventHandler (this. textbox1_textchanged)//In the code snippet generated by the Windows window designer in XXXXX.Designer.cs

Use EMGUCV's Imagebox () to open and display a pair of images in C #