Use java to realize the progressive shift of Arrays

Use java to implement an array loop step by step shift operation 1. the background teacher assigned several java programming questions in the class. This is one of them. design a class, add a constructor with a parameter, and encapsulate a method. When this method is called consecutively, the following elements are output in sequence: 5 7 4 8 9 1 2 call output: 1 5 7 4 8 9 3 call output: 9 1 5 7 4 8 4 call output: 8 9 1 5 7 4 5 call output: 4 8 9 1 5 7 6 call output: 7 4 8 9 1 5 3. code (with code explanation) [java] <span style = "font-family: SimSun; font-size: 14px"> package One; /*** @ author Kun Sun * @ Date: 2013.10.15 */public class Move {// mobile class int array []; public Move (int array []) {this. array = array;} private void movebit (int array []) {// shift method int temp; temp = array [array. length-1]; for (int I = array. length-1; I> 0; I --) {array [I] = array [I-1];} array [0] = temp;} public void talk () {// encapsulate movebit (array);} public void print (int array []) {// output int I = 0; for (I = 0; I <array. length; I ++) {System. out. print (array [I] + "");} System. out. println () ;}</span> [java] <span style = "font-family: SimSun; font-size: 14px"> package One; /*** @ author Kun Sun * @ Date: 2013.10.15 */public class MainClass {// used to test the mobile class/*** @ param args */public static void main (String [] args) {// TODO Auto-generated method stub int array [] = new int [] {5, 7, 4, 8, 9, 1}; Move move = new Move (array); int I = 0; while (I <6) {System. out. println ("no." + (I + 1) + "Call output:"); move. print (array); move. talk (); I ++ ;}}</span> 4. test Run result