What to do if a function return may throw an exception in Java

Source: Internet
Author: User
Protected Jsonobject doinbackground (String ... params) {

try {
return new Jsonparser (). Getjsonfromurl (Params[0]);
} catch (Jsonexception e) {
E.printstacktrace ();
}
finally {
Return? ;
}
}
The above code-reporting compilation error: Missing return value, but it seems to be unable to resolve AH. What is the appropriate value to return when an exception occurs? Do you want to manually assign a value
Jsonobject object?

What to do if a function return may throw an exception in Java

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