Codeforces Round #368 (DIV 2)__codeforces

昨晚的9點的CF,DIV2專場,為了rating change開了小號去。 說起來上一場也是DIV2專場開的小號去參加,然後第一個小號就上1900了,昨晚打完之後第二個小號也上DIV1了。蠻開心的。 最近這段時間在家裡大概是參加不了12點半的CF了。畢竟補充睡眠。 部分題解: Codeforces 707A Brain's Photos 題目連結:http://www.codeforces.com/problemset/problem/707/A 題意:給一個矩陣,

Codeforces 876 E. National Property (2-SAT)__圖論

Description You all know that the Library of Bookland is the largest library in the world. There are dozens of thousands of books in the library. Some long and uninteresting story was removed… The alphabet of Bookland is so large that

POJ 3414 Pots (BFS)__搜尋

Description You are given two pots, having the volume of A and B liters respectively. The following operations can be performed: FILL(i) fill the pot i (1 ≤ i ≤ 2) from the tap; DROP(i) empty the pot i to the drain; POUR(i,j)

分組的背包問題(背包九講)__動態規劃

問題:         有N件物品和一個容量為V的背包。第i件物品的費用是c[i],價值是w[i]。這些物品被劃分為若干組,每組中的物品互相衝突,最多選一件。求解將哪些物品裝入背包可使這些物品的費用總和不超過背包容量,且價值總和最大。 演算法:      

APK檔案結構和安裝過程

APK檔案結構 Android應用是用Java編寫的,利用Android SDK編譯代碼,並且把所有的資料和資源檔打包成一個APK (Android Package)檔案,這是一個尾碼名為.apk的壓縮檔,APK檔案中包含了一個Android應用程式的所有內容,是Android平台用於安裝應用程式的檔案。APK就是一個zip壓縮包,解開這個APK包我們可以看到以下的結構: Figure 1 APK檔案結構

POJ 3207 Ikki's Story IV - Panda's Trick (2-SAT)__圖論

Description liympanda, one of Ikki’s friend, likes playing games with Ikki. Today after minesweeping with Ikki and winning so many times, he is tired of such easy games and wants to play another game with Ikki. liympanda has a magic circle

POJ 3352 Road Construction (縮點)__圖論

Description It’s almost summer time, and that means that it’s almost summer construction time! This year, the good people who are in charge of the roads on the tropical island paradise of Remote Island would like to repair and upgrade the

動態規劃:HDU1712-ACboy needs your help(分組背包問題)__動態規劃-簡單DP

ACboy needs your help Time Limit : 1000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 4   Accepted Submission(s) : 1 Problem Description ACboy has N courses

51nod 1693 水群 (spfa)__圖論

Description 總所周知,水群是一件很浪費時間的事,但是其實在水群這件事中,也可以找到一些有意思的東西。 比如現在,bx2k就在研究怎樣水表情的問題。 首先,bx2k在對話方塊中輸入了一個表情��,接下來,他可以進行三種操作。 第一種,是全選複製,把所有表情全選然後複製到剪貼簿中。 第二種,是粘貼,把剪貼簿中的表情粘貼到對話方塊中。 第三種,是退格,把對話方塊中的最後一個表情刪去。

POJ3628 01背包__動態規劃、搜尋

Bookshelf 2 Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9037   Accepted: 4107 Description Farmer John

POJ 3683 Priest John's Busiest Day (2-SAT)__圖論

Description John is the only priest in his town. September 1st is the John’s busiest day in a year because there is an old legend in the town that the couple who get married on that day will be forever blessed by the God of Love. This year N

HDU 6214 Smallest Minimum Cut (最小割)__圖論

Description Consider a network G=(V,E) with source s and sink t. An s-t cut is a partition of nodes set V into two parts such that s and t belong to different parts. The cut set is the subset of E with all edges connecting nodes in different

HDU 6152 Friend-Graph (最大團)__圖論

Description It is well known that small groups are not conducive of the development of a team. Therefore, there shouldn’t be any small groups in a good team. In a team with n members,if there are three or more members are not friends with

Codeforces Round #301 (Div. 2) 解題報告(ABCD)__Codeforces

A Combination Lock         n位0~9密碼鎖兩種狀態之間,問最少撥多少次。注意可能越過'0'。直接上代碼。。 #include <bits/stdc++.h> using namespace std; char num1[1010];char num2[1010];int main(){int n;cin>>n;cin>>num1>>num2;int

HDU 2255 奔小康賺大錢 (二分圖最大權匹配)__圖論

Problem Description 傳說在遙遠的地方有一個非常富裕的村落,有一天,村長決定進行制度改革:重新分配房子。 這可是一件大事,關係到人民的房屋問題啊。村裡共有n間房間,剛好有n家老百姓,考慮到每家都要有房住(如果有老百姓沒房子住的話,容易引起不安定因素),每家必須分配到一間房子且只能得到一間房子。 另一方面,村長和另外的村領導希望得到最大的效益,這樣村裡的機構才會有錢.由於老百姓都比較富裕,他們都能對每一間房子在他們的經濟範圍內出一定的價格,比如有3間房子,

POJ3628 Bookshelf 2 01背包,水題__背包

就是在說給你幾種物品,然後做01背包,不比它給出的B小的第一個狀態是多少。 直接看代碼吧,太水了。 #include <cstdio>#include <cstring>#include <algorithm>#define N 25#define M 1001000using namespace std;int n,m;bool f[M];int

POJ 3126 Prime Path (BFS)__搜尋

Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-digit room numbers on their offices. — It is a matter of security to change such things

poj3628 Bookshelf 2 DP 01背包__poj

題目連結:http://poj.org/problem?id=3628 動態規劃第二題,還是純01背包 題意:就是給出n和b,然後給出n個數,用這n個數中的某些,求出一個和,這個和是>=b的最小值,輸出最小值與b的差。 分析:這裡的n個物品,每個物品的重量為c[i],價值為w[i]並且c[i]==w[i],,容量為所有c[i]的和sum。只要在f[]中從頭開始找,找到一個最小>=b的就是題目要的解

『圖論』LCA 最近公用祖先__圖論

轉載記得告訴千千哦~ 同步更新:https://www.dreamwings.cn/lca/4874.html 概述篇 LCA (Least Common Ancestors) ,即最近公用祖先,是指這樣的一個問題:在一棵有根樹中,找出某兩個節點 u 和 v 最近的公用祖先。   LCA 可分為線上演算法與離線演算法 線上演算法:指程式可以以序列化的方式一個一個處理輸入,也就是說在一開始並不需要知道所有的輸入。

Widget是什嗎?__google

最近看到Yahoo推出一種叫Widget的東西,連結如下: http://cn.widget.yahoo.com/ 進去看了看覺得像Google Desktop,不免險惡的揣測是不是模仿Google,進入Google lab之後就發現了這個: Google Dashboard Widgets for Mac 可惜是For Mac的 按照搜來的解釋: Widgetsn.小器具, 裝飾品n.[計]視窗小組件

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