checket

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The @override in Java

In the Java inheritance mechanism, subclasses can overwrite methods in the parent class. Base.java public class Base {public base () { System.out.println ("base"); } public void Foo () { System.out.println (' foo in Father '); } Checket.java: public class Checket extends Base {public checket () { super (); System.out.println ("Checket"); }

Several usages and differences of super and this in "Go" Java

Tag:ar use spjavaon data divbs code 1. Subclass constructors If you want to refer to super, you must put super in the first place of the function. class Base {base () {system.out.println ("base"); } }public class Checket extends Base {checket () {super ();//Call the constructor of the parent class, be sure to put it in the first statement of the method system.out.println ("

The difference between this and super in Java "6"

super cannot coexist, and the next one where this or super appears must be the 1th sentence of the construction method;Static methods, that is, cannot have this and Super keyword in a class method1. Subclass constructors If you want to refer to super, you must put super in the first place of the function. class Base {Base () {System.out.println ( "base" ); }} public class checket extends Base {Checket

Several uses of super in Java and the difference from this

1. Subclass constructors If you want to refer to super, you must put super in the first place of the function.class Base {Base () {System. out. println ("Base");}} Publicclass Checket extends Base {Checket () {Super ();//Call the constructor of the parent class, be sure to put it in the first statement of the methodSystem. out. println ("Checket");} PublicStatic

Detailed explanation of several usages of super in Java and the difference with this _java

1. Constructor of subclass if you want to refer to super, you must put super at the top of the function Copy Code code as follows: Class Base { Base () { System.out.println ("Base"); } } public class Checket extends Base { Checket () { Super ();//Call the Parent class construction method, be sure to place the first statement of the method System.out.println ("

The usage of super in Java and the difference with this

Reprinted from: http://blog.csdn.net/anmei2010/article/details/4093118 1. Sub-class constructor if you want to reference super, you must put super in the first place of the function. Class base {base () {system. out. println ("base") ;}} publicclass checketextends base {checket () {super (); // call the constructor of the parent class, which must be placed in the first statement system of the method. out. println ("

Several uses of super in Java, the difference from this

1. Subclass constructors If you want to refer to super, you must put super in the first place of the function. class Base {base () {System.out.println ("base"); }} public class Checket extends Base {checket () {super ();//Call the constructor of the parent class, be sure to place the first statement of the method System.out.println ("Che Cket "); } public static void Main (String argv[]) {

Several uses of super in Java and the difference from this

1. Subclass constructors If you want to refer to super, you must put super in the first place of the function . 1 classBase {2 Base () {3System.out.println ("Base");4 }5 }6 7 Public classChecketextendsBase {8 Checket () {9 Super();//call the constructor of the parent class, and be sure to put it in the first statement of the methodTenSystem.out.println ("Checket"); One } A - Public

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