android webview open link in external browser

I. OverviewWebview is a view that displays Web pages. It is based on your web browser or content that is only displayed in your activity.It uses the WebKit rendering engine to display webpages. It includes some methods: browsing records forward and backward, enlarging, downgrading, and text search.Implement built-in zoom in and out using websettings. setbuiltinzoomcontrols (Boolean ).Note: To enable your activity to access the Internet, you must add I

webviewclient{ - @Override $ PublicBoolean shouldoverrideurlloading (WebView view, String URL) { $ //TODO auto-generated Method Stub - view.loadurl (URL); - return true; the } - }Wuyi}The code is simple, and it gives the appropriate comments.Where the key code1 // set up a link to open a URL within the app 2 Webview.setwebviewclient (new webviewclient ()

This article describes how to invoke the WebView component of Android in unity to implement an internal browser-style page switch. First open eclipse to create an Android project:Unitytestactivity.java entry activity, unity will invoke the method in this activity to

Android provides an interface to encapsulate the browser, allowing developers to use their view to display Web content. Today, we have studied again, using WebView to display browser content, you can also use Webviewclient to display what you need.Reference: http://developer.android.com/reference/

You can use the browser that comes with the system to successfully play the flash, but you cannot play the flash with your own development. CodeAs follows:Browser = (webview) findviewbyid (R. Id. webview );Browser. getsettings (). setjavascriptenabled (true );Browser. gets

openFileChooser(uploadMsg, acceptType); } Openfilechooser is a hidden method.In this way, you can open a directory to upload files. However, in Versions later than 3.0, if the same webpage is opened in the android browser,There are also functions of photography and recording, and then directly upload the generated image or audio file, so we n

WebView under the pit odd, directly under the browser can directly bring up the camera and file management, but in WebView below is not, in the online review of a lot of articles, have to say pit odd, up to finally pieced together to succeed,Android version is 4.4.2, Debug Pass.Android Key Source:protected valuecallbac

Component location: Composite>webview. xml1 WebView2 android:id= "@+id/webview_pipeweb"3 android:layout_width= "match _parent "4 android:layout_height=" Match_parent "5 android:background=" @color/white "/ >. java1 Private WebView Webview_pipeweb; 2 3 webview_pipeweb = (webview) Findviewbyid (r.id.webview_pipeweb); 4 // setwebv

In predefined HTML files (suffixes may vary, but in the same format) addCan....Android browser with WebView, garbled problem

(buffer)) > 0) {randomfile.write (buffer,0, lenght); Debugtracetool.debugtracee ( This, "file length = =" +randomfile.length ()); } randomfile.close (); Httpget.abort (); } Catch(Exception e) {e.printstacktrace ();}Points to note:1. You need to start a single thread and cannot perform a file download operation on the main thread.2. Download the file name, length limit, the recommended file name length control at 100. Prevents the Ioexception:open failed:enametoolong (file name too long) e

Set the Quick Open External link method at install time: in the Sogou high-speed browser installation process, there is a step can be set to quickly open the external link, as shown in the following figure, check this here. Menu options Set Quick

The server can connect successfully, but in the browser cannot open any Web site, this problem is usually installed what software caused by IE settings made changes or the server is caused by the virus, or the server's DNS settings is wrong.First, check the server DNS is correctServer DNS is its own to resolve the domain name, if the DNS error, the server can not resolve the domain name, then the server can

); } } 3. Modify the Cocos2dxactivity.java under "Cocos2dx\platform\android\java\src\org\cocos2dx\lib" and add the following statement: 1 private static Activity me = null; 1 2 3) 4 5 protected void OnCreate (final Bundle savedinstancestate) {... me = this; ... } 1 2 3 4 5 6 public static void OpenURL (String url) {Intent i = new Intent (Intent.action_view); I.setdata (uri

Today, the boss gave me a need to ask me to investigate, he has tested the iOS platform is available, the requirement is simple is to enter a URI in the system browser to open the corresponding app.For example, you enter in the system browser of iOS: tel://123, will jump to call page and dial number is 123, like this command, eldest brother he used the millet pho

There are two methods: 1. CodeAs follows: IntentIntent = newIntent ();Intent. setaction ("android. Intent. Action. View "); Uri content_uri_browsers =Uri. parse ("content: // com.android.html fileprovider/sdcard/123.html ");Intent. setdata (content_uri_browsers );Intent. setclassname ("com. Android. Browser ","Com. Android