basic computer questions

12 questions about Wang becoming an academician Guangming Daily Editor's note: at the Seventh Council of the Chinese Computer Society held recently, Academician WANG became a special academic report titled: "Ask 12 questions about China's computer development ". Academician WANG believes that the reason for the rapi

. ' Hits ' is Null,0,message. ' Hits ') Hits,if (comment. ' id ' is null,0,count (*)) number From message left JOIN comment on message.id=comment.id GROUP by message. ' ID ' (3) The above Content management system, table category to save the classification information, the field is as follows (3 points) category_id Int (4) not NULL auto_increment; Categroy_name varchar (+) not null; When a user enters an article, select the article category by selecting the drop-down menu Write how to implement

, and the duplicate char is stored in ArrayList. We use the Collections.sort () function to sort the characters in the ArrayList, so the same characters must be contiguous. It then loops through the elements in the TreeSet collection, looking for the first and last occurrence of the element in ArrayList, the number of occurrences = The last occurrence-the number of occurrences of the first occurrence of +1.Second, the source codeProgram 1:Operation Result:Program 2:Operation Result:Program 3: O

word key that needs to be counted, then take advantage of Java's own indexof () Find the first occurrence of the word position,//statistics plus 1, and the previous statistics of the string truncated, in the remaining fields to match. int times = 0;while (true) {int index = Str.indexof (key), if (Index! =-1) {times++;str = str.substring (index + key.length ( ));} Else{return Times;}}}Operation Result:Source Code 3:Package Com.yue.day11;import Java.util.scanner;public class Yanghuitri {/** * Pri

); System.out.println ("Please enter the lower limit of the number:"); int low = Scanner.nextint (); System.out.println ("Please enter a number cap:"); int high = Scanner.nextint (); if (Low>high) {System.out.println ("you entered the wrong data, please re-enter!") "); System.out.println ("Please enter the lower limit of the number:"); low = Scanner.nextint (); System.out.println ("Please enter a number cap:"); high = Scanner.nextint ();} SYSTEM.OUT.PRINTLN (all primes between low+ "-" +high+ ")

) {Integer a = Integer.parseint (num);Long sum = 0;Long subsum = 0;for (int i=1;iSubsum = Subsum*10+a;sum = sum+subsum;}return sum;}}Operation Result:3. Procedure 3Package Tong.yue.hong;Import Java.util.Scanner;/** Title: If a number is exactly equal to the sum of its factors, this number is called the "end number", that is, the non-repetition factor other than itself and equal to itself. Programming to find all the finished numbers within M.* For example 6=1+2+3. The second complete number is 2

hundreds, 10 digits, single digit numbers are 1, 2, 3, 4. But must satisfy each one on the number is different, according to the permutation combination principle altogether has the 4*3*2=24 species. * @author Tong * */public class Pailiezuhe {public static void main (string[] args) {int count = 0;for (int i = 1; I Operation Result:3. Procedure 3Package Tong.yue.hong;import java.util.scanner;/** * The bonus awarded by the Enterprise is based on the profit commission. * Profit (I) less than or e

Computer Basics-hardware knowledge and basic computer hardware knowledge Computer Basics-hardware knowledge 1.Functions of programming languages: However, all languages are used for communication, such as Chinese and English. The essence of programmer programming is to allow computers to work, while programming languag

(original) A few questions should be paid attention to before applying for computer doctor---Write to graduating master graduates 1, the computer Doctor is what. Doctor and master are different, the doctor is sure to do research. Today, there are many school masters do not need to publish papers, not necessarily scientific research, may do some development and

The card computer boom triggered by Raspberry Pi has also led to the development of small-sized card computers by embedded developers in China. The well-known embedded developer in China, tianyinao technology and Feiling embedded system, also developed card computers. Now, we will compare the basic parameters of the embedded E8 chip computer with the OK335xS-II D

Java basic set classic Training Questions, java basic set classic Question 1: 10 random strings are required, each string is not repeated, and the characters (a-zA-Z0-9) in each string are also different, each string is 10; Analysis: * 1. When you see this question, you may think of many methods in your mind, such as determining whether the generated string conta

Huawei Computer Testing Questions (expression calculation-java), Huawei-java PS: Self-written, self-tested OK for your reference. /** Enter an expression (3*8 + 7-2) with no parentheses to output the result.*/ /* This program does not consider fault tolerance Processing for the moment */ 1 import java. util. iterator; 2 3 public class Calculator {4 5/* For example, in expression 3*8 + 7-2, dataNum = 4, opNu

Based on asp, jsp, java, vb and other computer science Graduation Design Questions Daquan, jspvb I found a lot and found it was a part of it. Many of them were incomplete. Then I sorted them through the network. If I was interested, I could leave my mailbox to send them. I have not found a place where I can upload objects.Paste two images. One is 36 pages in the document, covering most of the professional

Blue Bridge cup basic exercise leap year judgment [basic questions], Blue Bridge leap yearBasic exercise leap-year Judgment time limit: 1.0 s memory limit: 256.0 MBProblem description For a given year, determine whether the year is a leap year. This year is a leap year when one of the following conditions is met: 1. The year is a multiple of 4 rather than a mu

memory through the ing technology. But another problem is that there is no address bus. How can the CPU access the Rom? Even if the ing technology is used, you have to access the ROM first. There is also a conjecture that 32 address bus connects both Rom address space and Memory RAM. However, there are still doubts about how the CPU can access the ROM or Memory RAM at the same address, and the computer never permits ambiguity. I personally agree w

(1) von noriman's architecture The numeric system of a digital computer is binary. The computer should be executed in the program order. The computer consists of five parts: controller, memory, input device, and output device. (1) Controller The Controller is the entire computer's command center. It extracts the control information in the program. After analysis,

1. Calculate the sum of prime numbers greater than 1 in a string The number of input numbers cannot exceed 100. The number cannot exceed 10. The number of input groups must be 0. Example Input 4 1 2 3 4 5 1 2 3 4 5 0 Output 5 10 # Include 2. Compress strings A string containing only A-Z cannot exceed 1000 letters, and the same letter is compressed into duplicates + Subtitles (this forgets whether it is a multi-group input or a single group) Example Input Abbccc Output A2b3c #include 3.

#include "stdafx.h"#include July 2015 school recruitment-Huawei computer pen questions-multiplication of large numbers

Huawei Computer Testing Questions (convert digital string to binary-java), Huawei-java /** Title: convert a numeric string to a binary string Description: enter an integer to convert each integer to a binary number. If the last and third bits are "0", the output value is "0". If it is "1 ", output "1 ". Question category: bitwise operation Difficulty: elementary Score: 60 Run Time Limit: 10 Sec Memory limit

storedMOV R1, #78H; IN0 Channel locationMOV R2, #08H; analog channel numberMOVX @R1, A; start A/D conversionSETB IT0; external interrupt 0 is the Edge trigger modeSETB EX0; Allow external interrupt 0 interruptSETB EA; open CPU InterruptHere : SJMP hereEXINF0: PUSH PSW Protection siteCLR RS0CLSR RS1MOVX A, @R1; Read conversion resultsMOV @R0, A; Storage resultsINC R0INC R1DJNZ R2,next; 8 channel not finished, then take the next channelCLR EX0; After acquisition, stop interruptSJMP DoneNEXT: MOVX