edx java course

(Chapter II) > Package (without access modifier) > private8. About overloading8.1 must be in the same class, the method name is the same, the argument list is different (the number of method parameters or the parameter type is different), and the method return value and method modifiers have no relationship8.2 Overloaded matching method rules are from precise to fuzzy until a suitable method is found PackageOrg.lyrk.accp8.s2.chapter.one;/*** Created by Niechen on 17/4/17.*/ Public classTest8 {

internal masking details, external methods used to invoke, when to complete a function, we do not need to understand how this is implemented, just need to know to call this method to implement this function is goodTo illustrate:1 PackageCh11;2 3 /**4 * Student class, grammatical structure:5 * Public class class name {6 *//Properties7 * 8 * 9 *//MethodTen * } One * Created by Niechen on 17/5/13. A */ - classStudent { - /* the * syntax for defining attributes: - * Access modifier

Method Oneint c = n;N=m;M=c;TestSystem.out.println ("n=" +n+ "\nm=" +m);Method two with +-do exchangeint x=10,y=5;X=x+y; 5+20Y=x-y; 25-20X=x-y; 25-5System.out.println ("x=" +x+ "\ny=" +y); Three different ways or the highest efficiencyint a=2,b=4;A=a^b;B=a^b;A=a^b;System.out.println ("a=" +a+ "\nb=" +b);Expanding and taking anti-//// ////////////////////////////////////////////////////////Take counter/** Computer storage integer stored in source format, negative numbers stored in complementary f

* y;}}：Two ways to form an overloaded relationship:"(1) The method name is the same;(2) The parameter types are different, the number of parameters is different, or the order of the parameter types is different. "Program 7 is an int, square (7) calls an int square (int), resulting in the int type.Program 7.5 is a double type, square (7.5) calls a double square (double), resulting in double type resultsIt is known that the program is the overloading of the method, the first is the calculation of

Moonphases (read/write) Number of lines of code Posted Blog Volume/Blog comments number Classroom/Spare time study (hours) The most satisfying programming task First week 20/5 1/1 6/4 Experiment a job Second week 150/30 2/1 6/5 Lab two job integer programming Third week Week Four Week Five

voluminous. A: After the members of the reminder, I just re-read the teacher's lectures, found in the PPT gave a clear idea, so before it is to pay their own tuition bar. 2: Q: How do I prioritize an operator? A: At first I want to write a compare class that defines the precedence relationships of all operators in the class, determining the relationship between the top element and the current input operator when the suffix is turned, the output "Yes, it feels step-by-point toward the be

% Members of the group Project impressions Houzeian: This arithmetic, we do not do very well, add sub-items do not do, many times there is no time, from the beginning of the project did not plan the time of the whole project arrangements, and in the early completion of some slow. But in this project completed we also harvested a lot, including the use of stacks and the use of Stringtokenier methods, as well as the whole project planning and so on. The code Cloud link for the p

-consuming (minutes) Planning Plan 60 Estimate Estimate how long this task will take 3 Development Development 2000 3000 Analysis Demand analysis (including learning new technologies) 350 Coding Standard Code specification (to develop appropriate specifications for current development) 60 Design UML Design Project UML class diagram 60

Estimate Estimate how long this task will take 100 100 Development Development 800 Analysis Demand analysis (including learning new technologies) 100 Coding Standard Code specification (to develop appropriate specifications for current development) 30 Design UML Design Project UML class diagram 50 C

1 PackageCom.xunhuan;2 3 Public classZuoYe003 {4 5 6 Public Static voidMain (string[] args) {7 8 for(inti = 1; i//Enter for Loop, (I=1 i9 if(i%3==0i%5==0) {//If judgment I take 3 no remainder, and I take more than 5 no remainder into if, the output is a multiple of 3 and 5TenSystem.out.println ("Filpflop"); One}Else if(i%3==0) {//does not satisfy if enter else if,i take-out 3==0, multiples of output 3 ASystem.out.println ("Filp"); -}Else if(i%5==0) {//does not satisfy

1 PackageCom.xunhuan;2 3 Public classZUOYE02 {4 5 Public Static voidMain (string[] args) {6 intA = 0;7 intb = 1 ;8 Do {9 if(b%7==0) {//First Judge B is not the remainder, if there is no remainder proof is a multiple of 7TenA=a+b;//calculates the number of the other with a multiple of 7 One}b++; A} while(B//B is less than - System.out.println (a); - the } - -}Java Fundamentals (fifth post-

1 PackageCom.xunhuan;2 3 ImportJava.util.Scanner;4 5 Public classZuoYe03 {6 7 8 Public Static voidMain (string[] args) {9Scanner meng00=NewScanner (system.in);Ten One A intmun; - intMax=0; - intMin=0; the - //Enter Do...while loop output - Do { -System.out.println ("Please enter a number (enter 0 to end)"); +Mun =meng00.nextint (); - if(mun!=0) {//If you determine the number of inputs if not equal to 0, enter

Moonphases (read/write) Number of lines of code Post a blog volume/comment on the number of others ' blogs Time after school (hours) Learn the most rewarding program reading or programming tasks First week 20/10 1/0 5 Output 99 multiplication table using the Elipse development program Second week 60/20 1/0 6 Experiment Seven experiment Five Third week Week F