good book for data structures and algorithms

() method in the Bubblesort.java program (listing 3.1) with the Oddevensort () method . Make sure it runs in a sort of different amount of data, and that you need to figure out the number of two scans. Parity Ordering is actually useful in multiprocessor environments where the processor can process each odd pair at the same time, and then handle even pairs at the same time. Because the odd pairs are independent of each other, each pair can be compar

all cases:650) this.width=650; "src=" Http://files.jb51.net/file_images/article/201211/2012110120523847.png "/>void Clear (); empty queue; Initial conditions: queue exists; operation result: Leave the queue empty.void in (T item); Queued Initial conditions: queue exists; action Result: Adds a new data element with a value of item to the end of the queue, and the queues are changed.650) this.width=650; "Width=" 620 "height=" 437 "src=" http://files.jb

Binary tree node:/** Binary tree node*/public class Node {Data itempublic Long data;Left Dial Hand nodePublic Node Leftchild;Right child nodePublic Node Rightchild;/*** Construction Method* @param data*/Public Node (Long data) {This.data = data;}}Binary Tree class:/** Two-fo

(recorded as n) should be equal to the sum of 0 degree nodes, 1 degree nodes (recorded as N1) and 2 degree nodes:N=NO+N1+N2 (Formula 1)On the other hand, 1-degree nodes have a child, 2-degree nodes have two children, so the total number of child nodes in the binary tree is:Nl+2n2Only the root node in the tree is not a child of any node, so the total number of nodes in the binary tree can be expressed as:N=n1+2n2+1 (Formula 2)obtained by the Formula 1 and the 2:No=n2+1"

filtering is the Bloom filter (Bron filter). The Bron filter principle is simply: Create a large bit array, then hash the same URL with multiple hash functions to get multiple numbers, and then position the digits in the bit array at 1. Next time a URL, the same is used to hash the hash function, to get multiple numbers, we only need to determine the bit array of these numbers corresponding to is all 1, if all is 1, then the URL has appeared. This completes the URL-heavy issue. Of course, this

= mid#determine the starting subscript for the post-half string - Else: -Next = mid + 1 the -top = Mid-1 - forIinchRange (Next,len (A)): - ifStack[top]! =A[i]: + returnFalse -Top-= 1 + A returnTrueTest:if __name__= ="__main__" := List ("Hahahahahahahahaha ") print is_plalindrome_demo1 (q)Manual implementation Stack1 #simple filo stack category2 classStack:3 def __init__(self):4Self.top = None#point to top of stack5Self.end = None#Point to the bo

field to delete*/Public Node Delete (Long value) {Node current = first;Node previous = first;while (current.data! = value) {if (Current.next = = null) {return null;}previous = current;current = Current.next;}if (current = = first) {first = First.next;} else {Previous.next = Current.next;}return current;}}Test:public class Testlinklist {public static void Main (string[] args) {linklist linklist = new linklist ();Linklist.insertfirst (34);Linklist.insertfirst (23);Linklist.insertfirst (12);Linkli

string into the object.Remove removes the character from the StringBuilder object. Two parameters: The starting position and the number of characters to remove. ‘Replace: Replaces the character of the StringBuilder object. Two parameters: The old string to replace and the new string to replace.When working with StringBuilder objects, it is often necessary to convert them into strings, which can be implemented using the ToString method. Returns a string instance in the StringBuilder instance.C #

does not support the comparison size.-priority the priority counter, ensuring that the smallest element function in the queue (the most important) is always placed in _queue[0]. heapq.heappush()and the first element is heapq.heappop() inserted and deleted separately on the queue, the _queue first element of the _queue is always the smallest, ensuring that the queue _queue the first element with the highest priority.Reference: "Python Cookbook" 3rd EditionHttp://python3-cookbook.readthedocs.io/z

Implementation of the collectionfunction Set () {this.datastore = []; This.add = add; This.remove = remove; this.size = size; this.union = Union; This.intersect = intersect; This.subset = subset; this.difference = difference; This.show = Show; This.contains = contains;} function Add (data) {if (this.dataStore.indexOf (data) Practice one. Modify the collection class so that the

issue. It is great article to use relational databases to access or to use NoSQL, or to design specific file formats for storage.6) Inter-process communicationDistributed crawler, it is necessary to rely on inter-process communication. We can interact with data in the specified data format to complete interprocess communication.7) ...Nonsense said so much, the real problem comes, the problem is not to lear

) { +Temp[i] =key; -}Else { theTemp[i] = This. table[i-1];Bayi } the } the - This. Table =temp; - } the the Public intSearchindex (intkey) { the intn = key/m-1; the intStart =-1; - intLength =-1; the //Find index location the for(inti = 0; I This. Indextable.size (); i++) { the if(n = = This. Indextable.get (i). Index) {94Start = This. Indextable.get (i). Start; theLength = This. Indextable.get (i). len

This is my third side of the question summary.To see the previous content, please visit:http://zhweizhi.blog.51cto.com/10800691/1763237(Some data structure algorithm surface question "One" (update completed))http://zhweizhi.blog.51cto.com/10800691/1775780(Some data structure algorithm surface question "Two" (update completed))http://zhweizhi.blog.51cto.com/10800691/1787562(Some

their definitions into a hash list; The second part lets the user enter a word, and the program gives the definition of the word.// 字典类function Dict () { this.hashTable = new HashTable(); this.save = save; this.find = find;}function save (word, description) { this.hashTable.put(word, description);}function find (word) { return this.hashTable.get(word);}// 示例let d = new Dict();d.save('Mazey', 'a strong man.');d.save('Cherrie', 'a beautiful girl.');d.save('John', 'unknown.');consol

){ if(Array[j] key) {Array[i+ +] = Array[j];//A[i] = a[j]; i + = 1; Break; }; } for(; i ){ if(Array[i] >key) {Array[j--] =Array[i]; Break; }}} Array[i]=key; Sort (0, i); Sort (i+ 1, numsize); }} sort (0, Array.Length); returnArray;}There is also an easy-to-understand approach:Set two empty arrays left and right, traverse the entire array, and push in to leave if it encounters less critical

From coolshell (from a website: data structure visualizations) Do you still remember the previous article about visual sorting? On the Internet, I saw a home page for various visual data structures and basic algorithms by David galles from the University of San Francisco. The website is here for you to see. I listed t

Stacks and queuesStack (last in, first out)Stack, which allows access to only one data item: The last inserted data item.Stacks can be used to check the matching problems of parentheses and parse mathematical expressions, similar to those used in the compilation principle.The operation of the picture is actually summed up: 1. Read the left delimiter into the stack, 2. The right delimiter is read to match th

) + (N-2) +...+1 = N (N-1)/2When the value of N is very large, the algorithm compares the number of N2/2 times, ignoring minus 1.Assuming that the data is random, it is possible to swap locations each time, possibly without swapping, assuming a probability of 50%, then the number of interchanges is N2/4. However, if the worst-case scenario is that the initial data is reversed, the position is swapped for ea

node without any child nodes.The number of layers in the two-ary tree is L, and the node points are N, then N=2L-1;L=LOG2 (n+1).5. Complete binary TreeConcept: In addition to the last layer, each of the other layers of the number of nodes are full, the last layer if also full, is a full two fork tree, is also a complete binary tree. If the last layer is dissatisfied, the missing nodes are all concentrated on the right, and that is a tree full of two forks.As below, are completely binary tree!!!

,elemtype e){int j,k,l;K = max_size-1;if (i{return ERROR;}j = malloc_sll (L);//Call the function written above,if (j){L[j].data = e;for (l=1;l{K = L[k].cur;}L[j].cur = L[k].cur;L[k].cur = j;return OK;}return ERROR;}Delete operation650) this.width=650; "title=" 11.jpg "src=" http://s3.51cto.com/wyfs02/M02/57/28/wKioL1STg1TTn7fqAAHvw03C2fQ503.jpg "alt=" Wkiol1stg1ttn7fqaahvw03c2fq503.jpg "/>Sample codeStatus Listinsert (staticlinklist l,int i){int j,k;K