gray balloons

Test instructions is easy to understand: Limak can give their own balloons to others, so that other people's balloons than weight. Thus allowing others to float on the ceiling, unable to participate in the rankings, thus making limak their rankings rise. This topic is a typical greedy, when limak his own balloon to others, his own hands of the balloon will be reduced, then his own ranking is likely to be re

Save GamesThe other half comes from the end of the game. Our team has3balloons. Galready have the idea,AQuestionsSJand theWZin the discussion, it seems to have the result. BQuestionsBQZThe team has come out. See in the distantBQZTeam of blue balloons, with the team said. They can all make out the topic. We can't .Adon't come out! At that time I was a little impetuous, I said to all, another 1.5 hours, we can come out6a question, you have confidence in

Long time no title has been no state and then brush a water problem to playWinter vacation Training and school games have done a similar topic but then did not (in fact, now will notTest instructions: There are k balloons and an n-storey building, the balloon has a hardness, in some would have just broken, ask at least how many times the experiment can be found just broken floor.Solution: Divided into two cases: the current floor broken, the current f

Source: http://acm.fzu.edu.cn/problem.php? PID = 1515 Fuzhou University oj15 There is a cube box that provides the coordinates of two vertices on the diagonal corner. in this box, there are N points, where n Because there are only 6 balloons in total, there are 6 in total! = 720 expansion schemes. it is easy to think of enumeration because there are few cases. use DFS to find the order of each expansion scheme, and then obtain the distance from eac

Turn from http://www.cnblogs.com/tiandsp/archive/2012/01/07/2316006.html thanks to DSP TianClearCLCimg = imread (' 124.jpg '); % Read image from graphics file[m n T] = size (IMG); % Get pattern sizemax = 0;min = 256;Avg = 0;For I =1:1:mfor j = 1:1:nIf IMG (i,j) Min = img (i,j);EndIf IMG (i,j) >maxMax = img (i,j);EndAVG = AVG +double (img (i, j));EndEndAvg = uint8 (avg/(m*n));MNTMaxMinAvgHow to read and write image files in MATLAB and simple processing of imagesThe MATLAB image processing Toolbox

The idea of the problem is very difficult to think about. Asking the minimum number of experiments you need is very difficult to solve. And we know that there are only three conditions. K, N, number of experiments.So we'd better change our mind and turn to the highest number of floors we can determine. Then use D[I][J] to indicate the maximum number of floors that can be determined with the I-ball and the J-time of the experiment.So if we're on the K-floor, there are two possibilities: 1, the ba

2018-10-03 19:29:43Problem Description:Problem solving:Very interesting topic, the first thought is the violent traversal solution space, of course, also used to memo, unfortunately or tle, because time complexity is indeed a bit too high, it should be O (n!). MapThe main subject gives the data scale, has already indicated that the time complexity is O (n^3) around more appropriate. The standard solution of the subject is given below, and the dynamic programming algorithm is used.Dp[i][j]:nums[i

#include #includeusing namespacestd;Const intMAXK = -;Const intMaxa = the; unsignedLong Longd[maxk+1][maxa+1];intMain () {memset (d,0,sizeof(d)); for(inti =1; I ) for(intj =1; J ) D[i][j]= d[i-1][j-1] +1+ d[i][j-1]; intK; unsignedLong LongN; while(Cin >> k >> N k) {intAns =-1; for(inti =1; I ) if(D[k][i] >=N) {ans=i; Break; } if(Ans 0) cout"More than""Trials needed.\n"; Elsecout"\ n"; } return 0;}uva10934 Dropping water balloons

, Tan2, tan=0; intI, J, Z, Lnor, Lrot, X, y; Init (); for(i=1; ii) for(j=1; jj) {Node No, RO; Lrot=lnor=MAXN; //Normal for(z=0;z8; z+=2) Lnor=min (Lnor, DP[Z][I][J].L), no=no+Dp[z][i][j]; for(z=0;z8; z+=2) { if(dp[z][i][j].l>Lnor) {x=i+dx[z]* (Lnor); y=j+dy[z]*(Lnor); No=no-Dp[z][x][y]; } } //Rotate for(z=1;z8; z+=2) Lrot=min (Lrot, DP[Z][I][J].L), ro=ro+Dp[z][i][j]; for(z=1;z8; z+=2) { if(dp[

AI and water level bi for the flood of the first I, and count how many bridges have been flooded at least k times. The initial water level is 1, and the swollen water level of each flood must be greater than the water level of the last flood.InputThe input file contains up to 25 sets of test data. The first behavior of each group of data is three integers n, m, K (1OutputFor each set of data, output the number of bridges that have been flooded at least k times.Sample Input2 2 22 56 28 35 3 22 3

This tutorial uses Photoshop to draw the lovely balloon WordArt tutorial, the production of balloons is relatively cumbersome, because the high light and dark areas are not very regular, not directly with the layer style to complete, you need to use a pen to check out the outline of each part, into the selection after the corresponding color fill. Like friends let us study together. Final effect 1, click here to download the PSD material

In the code of a group of numbers, if any two adjacent code is different from only one binary number, it is said that this code is gray code (gray code), gray code is composed of 0 and 1, the binary code evolved.The Gray code generation method is as follows: 1-bit gray