Use case Overview: Determine whether it is a leap year based on the age of input and determine if there is a fault tolerant techniqueTest environment: EclipseTest Objective: To determine whether a leap year, and to determine whether there is fault-tolerant technologyUser requirements: Determine whether the input age is
Create a new Form application (below) and create a new control Label1,label2,label3,textbox1,button1,button2Change the Text property of Label1 to "Calculate Leap year Demo"Change the Text property of Label2 to "enter year"Change the Text property of button1 to "OK"Change the Text property of button1 to "exit"Full code:1 usingSystem;2 usingSystem.Collections.Gener
Problem DescriptionEnter the year to determine if the leap yearsInputEnter an integer n (multiple sets of data)OutputIf it is a leap year, output Yes, otherwise output no (one row per group of data)Sample Input2000Sample OutputYesMy Code:1#include 2 intMain ()3 { 4 intYear ;5 while(SCANF ("%d",
Leap Year CalculatorTitle: Enter the year to determine if the year is a leap years.Method: 1. Year that can be divisible by 4002. Can be divisible by 4, but not divisible by 1001 Print('---Lea
(' illegal input ');//NOTE: Test data type echo GetType ($year);//At this time $year is a number type, judging whether it is an integer if (Is_int ($year)) { //main program if ($year
or method Two: Strpos ($year, '
[Java]/* (Start of program header annotation) * Copyright (c) 2011, a student from the computer College of Yantai University* Author: Li Zhaoqing* Completion date: January 1, September 22, 2012* Input description:* Problem description and output: run java: enter a year on the keyboard to determine whether it is a leap year
When reading "Javascript practice", Chapter 3 describes how to create a package. There is a datetime package which provides two methods: one is to determine whether a year is a leap year, determines the number of days in a month and considers the leap year. let's take a look
First, Leap year definitionThe number of non-whole hundred years, divisible by 4 for a leap year, the whole hundred years, divisible by 400 is a leap year.For example: 1996 is a leap year
Import Java.util.Scanner;
public class Leapyear {public
static void Main (string[] arg) {
Scanner scan = new Scanner (system.in);
System.out.println ("Please enter a year:");
Long year= Scan.nextlong ();
if (year%4==0 year%100!=0 | | year%400 ==0) {
1#include 2 intIsleap (intyear ) {3 //the case of a leap year must first be judged by the case of common year4 if((year% -==0 year% -!=0) || year%3200==0) {5 //is not a leap ye
usingSystem;usingSystem.Collections.Generic;usingSystem.Linq;usingSystem.Text;usingSystem.Threading.Tasks;namespaceleap year Exercise {classProgram {Static voidMain (string[] args) { //1, enter the month and day, see whether the date entered is correct//2. Whether the output is a leap year (29 days), the output date//
A number is entered by the client to determine whether it is a leap year This is the JSP page (the page that provides action to the client)@ Page Language="Java"ContentType="text/html; Charset=utf-8"pageencoding="UTF-8"%> @ Page Import="Com.liaoyuanping.action.isLeap" %>-This is the Isleap class method referenced in Java codeDOCTYPE HTML PUBLIC "-//w3c//dtd HTML 4.01 transitional//en" "Http://www.w3.org/TR/
The condition of a leap year is one of the following two conditions:1, can be divisible by 4, but not divisible by 100;2, divisible by 4, and divisible by 400. Because it can be divisible by 400, it must be divisible by 4, soThe second condition can be simplified to be divisible by 400.0==y%4 (0!=y%100 | | 0==y%400)
function Fn_validatedate (nyear, Nmonth, Nday){if (Nmonth if (Nday if (Nmonth = 4 | |
The calculated leap year is mainly to determine the number of days in February, the general leap year February is 29 days, excepting February is 28 days. The algorithm for calculating a leap year is very simple: it can be divisibl
Tags: case span creat ret Sele font leap year RAC variable --Calculate the number of days for flat leapfunction
CREATE OR REPLACE FUNCTIONF_ping_run_nian (i_year Number --define function Names
)
RETURN VARCHAR2 is --defines the return (output) character type
V_tianshuvarchar2(5);--defining output (return) variables
BEG
#coding = Utf-8defgetlastday (): Y= Int (Input ("Please input year:")) M= Int (Input ("Please input month:")) d= Int (Input ("Please input day:")) S=0ifY : Y=1ifM : M=1ifM>12: M=12ifD : D=1Mothday=[31,28,31,30,31,30,31,31,30,31,30,31]#number of days per month in a yearMONTH=MOTHDAY[M-1]#get the number of days to enter a month ifD > Mothday[m-1]:#determine if the input date is greater than the number of monthsD=d-mothday[m-1] M+=1Month=MOTHDAY[M-1]#
C # explain the if branch statement and example (an example of determining whether it is a leap year ),
I. if branch statement
1,Add # region # endregion at the beginning and end, comment it out, and the code will be foldable. The Code will be clearer and the minus sign will be added before the point.
2,
(1)If (expression)
{
Statement block executed after expression is set up
}
Follow F11 to view and execu
To see the source code:
Copy Code code as follows:
/**
* Jscript.datetime Package
* This package contains utility functions for working with dates and times.
*/
/* Namespace */
if (typeof JScript = = ' undefined ') {
JScript = function () {}
}
Jscript.datetime = function () {}
/**
* This function would return the number of days in a given month and year,
* Taking leap years into
Judge whether the year is a leap years!#!/usr/bin/env pythonye = Int (raw_input (' Please enter the Year: ')) if ye% = = 0:if (ye/100)% 4 = = 0:Print "Your inputing is a leap year!" Else:print "Your inputing is not a leap
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