m17 r3

Simplest computer Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others)Total submission (s): 1781 accepted submission (s): 1054 Problem description a research organization named pigheadthree designed a computer for experiment named PPMM. PPMM can only execute six simple commands a, B, c, d, e, f; only two memory M1, M2; three registers R1, R2, R3. The meaning of the six commands is as follows: Command A: load the data of me

-0x2a007000 is. got0x2a007000-0x2a0070c0 is. data0x2a0070c0-0x2a01a1ee is. bss........(Gdb) x/32i 0x2a001078 // view the new text segment Assembly command to find the libc_init call0x2a001078: push {r11, lr}0x2a000000c: add r11, sp, #40x2a001080: sub sp, sp, #160x2a001084: ldr r3, [pc, #80]; 0x2a0010dc0x2a001088: add r3, pc, r30x2a0020.c: ldr r2, [pc, #76]; 0x2a0010e00x2a001090: ldr r2, [

We all know the essential differences between IPv6 and IPv4 protocol networks. So what are the differences between the two in the two-way session communication process? The following describes the content in detail. The NAT-PT can only be used for applications that initiate a session by a terminal in the Ipv6 network, and the NAT-PT cannot be implemented if an application needs to initiate a session by a terminal in the IPv4 protocol network, because the terminal in the IPv4 protocol network can

The neighbor state machine after the mtu value of the H3C OSPF interface has been studying the OSPF principle and configuration of H3C over the past few days. Now there are two routers R3 and R4 connected through their respective Ethernet ports E0/0, after configuring the IP address and OSPF correctly, modify the mtu value of the R3 E0/0 interface to 1000 (1500 by default) and restart the OSPF process of

to access the router R3 the host 192.168.7.1/24 need to be implemented by the following process: First, the routing r1/r2/r3 can and can only know its direct-attached network through its interface address and mask when there is no routing protocol, so its direct-attached network routing information is as follows: R1:192.168.1.0/24 (direct) 192.168.2.0/24 (direct) 192.168.3.0/24 (direct)R2:192

Cough... Some of the code that I wrote recently is a Review ... But ... I don't know what kind of a ... The ps:php version is 5.4 so don't tangle [] what's up ... This is the array. 1$rule = [' pid=etfscreenerformsubmit=1etfpage=1cn=cnuscf=go=ta=er=er1 Ry=r1=r3=r5=tac=1erc=1ryc=1r5c=1 ', ' pid=etfscreenerformsubmit=1 Etfpage=1cn=cnuscf=go=ta=er=er2ry=r1=r3=r5=tac=1erc=1 ryc=1r5c=1 ', ' pid=etfscreenerforms

Let's start with some basic knowledge of arm assembly. (We take ARMV7 as an example, the latest iphone5s on the 64-bit is not discussed) Basic Knowledge Section: First you introduce registers: R0-R3: For the transfer of function parameters and return values R4-R6, R8,r10-r11: There is no special provision, is the general General register R7: Stack frame pointer (frame pointer). Point to the address of the previous saved stack frame (stack frame)

Installing JenkinsMode One: Docker mode installationPull the official Jenkins image and start mirroring in the mirrored document.Mode two: Manual installationAll of the following actions are performed using the root user.Download Java, Tomcat, Jenkins on each project websiteJava:http://www.oracle.com/technetwork/java/javase/downloads/jdk8-downloads-2133151.html tomcat:http:// tomcat.apache.org/download-90.cgi Jen jenkins:https://jenkins.io/Environment used: jdk1.8.0_121 Tomcat-9.0.0.

650) this. width = 650; "src =" http://img1.51cto.com/attachment/201309/163818372.jpg "title =" QQ20130925160851.jpg "alt =" 163818372.jpg"/> Lab environment: R1 uplink lines are R2 and R3 respectively, R2, R3, and R4 communicate through OSPF. Purpose: By default, C1 accesses R4 through the connection between R1 and R2. If the line between R1 and R2 is interrupted, R4. By default, C2 accesses R4 through th

Cough... some recently written code has CodeReview... but... I don't know which one can pass... PS: the PHP version is 5.4, so don't worry about [] what it is... this is array {code ...} cough... some recently written Code has Code Review... But... I don't know which one can pass... PS: PHP version 5.4, so don't worry about [] What is... This is array // 1$rule = ['pid=etfscreenerformsubmit=1etfpage=1cn=cnUScf=go=ta=er=er1ry=r1=r3=r5=tac=1erc=1ryc=1r

. Data0x2a0070c0-0x2a01a1ee is. BSS........(GDB) X/32i 0x2a001078//View new text Segment assembly instructions to find Libc_init call0x2a001078:push {R11, LR}0x2a00107c:add R11, SP, #40x2a001080:sub sp, SP, #160X2A001084:LDR R3, [PC, #80]; 0x2a0010dc0x2a001088:add R3, PC, R30x2a00108c:ldr R2, [pc, #76]; 0x2a0010e00x2a001090:ldr R2, [R3, R2]0x2a001094:str R2, [R11

Title: n matrix multiplication, to find the least number of multiply operations and how to combineSuppose that matrix A is r1*r2 and matrix B is R2*R3, so m=a*b=r1*r2*r3. When multiple matrices are multiplied, the number of operations is different when the matrix is combined in different ways.Example: M=M1 * M2 * M3 * M4[5*20] [20*50] [50*1] [1*100]((m1*m2) *m3) *m4=5000+250+500=5750and M1* (m2* (M3*M4))

A-aTime Limit:1000MSMemory Limit:32768KB64bit IO Format:%LLD %llusubmit Status Practice Lightoj 1331DescriptionAgent J is preparing-steal an antique diamond piece from a museum. As it is fully guarded and they was guarding it using high technologies, it's not easy to steal the piece. There is three circular laser scanners in the museum which is the main headache for Agent J. The scanners is centered in a certain position, and they keep rotating maintaining a certain radius. And they is placed su

/*ProblemsRanklistStatusStatisticsThe simplest computerTime limit:2000/1000ms (java/other) Memory limit:65536/32768k (Java/other)Total submission (s): Accepted submission (s): 4Font:times New Roman | Verdana | GeorgiaFont size:←→Problem DescriptionA research organization called Pigheadthree designed an experimental computer named PPMM. PPMM can only perform a simple six command a,b,c,d,e,f, only two memory m1,m2, and three registers of R1,R2,R3. The s

compares the sizes of two operands.ADD R3, R2, R1, LSR #2; R3R2 + R1 limit 4ADD R3, R2, R1, LSR R4; R3R2 + R1 20172r4LDR R0, [R1]; R0 1_[ R1] transfers the data in the memory with the R1 value as the address to R0.STR R0, [R1]; [R1] 1_r0 transfers the R0 value to the memory where the R1 value is the address.Base Address addressingLDR R0, [R1, #4]; R0 1_[ R1 + 4]LDR R0, [R1, #4]!; R0 1_[ R1 + 4], R1 1_r1 +

the Swapper page Table///////////////////16bytes page Empty mov r0, r4 mov r3, #0 add R6, R0, #PG_DIR_SIZE1: STR R3, [r0], #4 str R3, [r0], #4 str R3, [R0], #4 s TR R3, [R0], #4 teq r0, R6 BNE 1b//If you define CONFIG_ARM_LPAE, add a second page table before PGD and PMD

and 0x802 are both illegal and immediate numbers, they cannot be manipulated directly.The above steps are related to the CPU cache and the MMU, do not have to look closely, probably know. Boot Media Selection /* Read Booting information */ LDR r0, =pro_id_base ldr R1, [R0, #OMR_OFFSET]/ * r1=0xe0000004 */ BIC R2, R 1, #0xffffffc1 NAND BOOT */ CMP R2, #0x0 @ 512B 4-cycle/ * NAND The page size is 512b,4 instruction cycle *

table is all a, that is, A1,a2,..., An, then you can immediately conclude that P-phase for F is lossless connection decomposition, at this time no longer need to continue to modify. If the table does not have a row full of a, then the decomposition is lossy, after several modifications until the form cannot be modified. 　　It is important to note that there is a process of looping over and over again, because one modification can cause the table to continue to be modified. In the process of modi

Problem: I took an eclipse Maven project with my colleague and imported an error, mainly showing a child container failed during startSpecific errors are as followsJune 02, 2018 12:08:50pm Org.apache.tomcat.util.digester.SetPropertiesRule begin WARNING: [Setpropertiesrule]{server/service/engine/host/context} Setting ' source ' to ' org.eclipse.jst.jee.server:UcomWechat 'Did not find a matching property. June02, 2018 12:08:50pm Org.apache.catalina.startup.VersionLoggerListener Log information: Se

192.168.2.0 0.0.0.255Vror3 R3 Configuration: www.2cto.com [R3] int e1 [R3-Ethernet1] ip add 192.168.2.2 255.255.255.0 [R3-Ethernet1] int s0 [R3-Serial0] ip add 192.168.3.1 255.255.255.255.0 [R3-Serial0] quit [