m17 r3

Both RIPv2 and RIPng use a metric of value 1-16 (for hops), a maximum hop count of 15,16 means unreachable, and the router increments the measure when a routing update is received, but there are significant differences between ripng and RIPv2 processing methods, which are analyzed by experiments;650) this.width=650; "src=" http://s3.51cto.com/wyfs02/M02/58/D4/wKiom1S9zvCQl6koAADm6MwSb-I502.jpg "title=" 3.png " alt= "Wkiom1s9zvcql6koaadm6mwsb-i502.jpg"/>R1, R2,

100 port tracking, priority reduced by 100 R2 Configuration R2 (config) # int f0/0r2 (config-if) # ip add 192.168.1.2 255.255.255.0 R2 (config-if) # no shu R2 (config-if) # int f1/0 R2 (config-if) # ip add 192.168.3.1 255.255.255.0 R2 (config-if) # no shu R2 (config) # router rip R2 (config-router) # network 192.168.1.0 R2 (config-router) # network 192.168.3.0 R2 (config) # int f0/0 R2 (config-if) # standby 47 ip address 192.168.1.254 the backup group is 47 and the vir

R1 (config-if) # ip nat inside R1 (config-if) # ex R1 (config) # ip nat inside source list 101 pool pool1 overload // map acl101 to pool1 R1 (config) # ip nat inside source list 102 pool pool2 overload // map acl102 to pool2 R1 (config) # ip route 192.168.2.0 255.255.255.0 192.168.4.2 // route to municipal Ethernet R1 (config) # ip route 192.168.3.0 255.255.255.0 192.168.5.2 // route to the provincial Ethernet R1 (config) # end R2 Router # config t Router (config) # line con 0 Router

1. Set up an experimental environment: DynamipsGUI, SecureCRT, CiscoIOS image file for unzip-c3640-ik9o3s-mz.124-10.bin 650) this. width = 650; "onclick = 'window. open (" http://blog.51cto.com/viewpic.php? Refimg = "+ this. src) 'height = "282" border = "0" src = "http://www.bkjia.com/uploads/allimg/131227/040PV411-0.jpg" alt = "clip_image002" style = "border: 0px none;" title = "clip_image002"/> R1 simulates the branch router, R2 simulates the Internet, and

Concept preview: What is multi-point bidirectional routing re-release?Different routing protocols send route information to each other through re-publishing. The number of ASBR routers for re-publishing is more than one. in each routing protocol, the ASBR can receive the route information re-published by each other.I. Experiment topology: 650) this. width = 650; "alt =" "src =" http://www.bkjia.com/uploads/allimg/131227/0300461343-0.jpg "border =" 0 "/> Ii. Purpose:Dual-point: for the sake of r

[Lab environment] The C3640-IK9O3S-M Version 12.4 (10) [PURPOSE] BGP Confederation is used to solve the BGP Route black hole problem caused by horizontal segmentation of IBGP. [Experiment topology] [Experiment description] R1, R2, R4, and R5 run the BGP protocol, while R2, R3, and R4 run the OSPF protocol. The objective is to make 1.1.1.1 The IBGP neighbor relationship is established using the loopback interface. Use a direct connection interface be

route learning is completely normal, and R3 cannot learn any route 14.8. Analyze the causes of these faults and troubleshoot the faults without changing the original configuration. Original configuration for fault generation: the original configuration for fault generation is as follows. Original configuration of router R1: Interface Loopback1 Ip address 192.168.5.1 255.255.255.0 ! InterfaceEthernet1/0 Ip address 192.168.2.1 255.255.255.0 Ip a

Technorati Tags: mpls,bgp,ccie, tags, LDPWill LDP assign tags to BGP routes? Why?650) this.width=650; "Style=" background-image:none;border-bottom:0px;border-left:0px;padding-left:0px; padding-right:0px;border-top:0px;border-right:0px;padding-top:0px; "title=" clip_image002 "border=" 0 "alt=" clip_ image002 "src=" http://s3.51cto.com/wyfs02/M02/73/F4/wKiom1YKXeDji6JDAADrM1sEj0Q970.jpg "height=" 178 "/>Before---We said that LDP assigns tags to IGP and never says to assign a label to BGP.Here's an

0x04Und_stack_size equ 0x04Svc_stack_size equ 0x04User_stack_size equ 0x100 ;----------------------------------------------------------------------------9200 clock changes after startupBecause the system enters the slow clock Status After resetting, the host clock source is provided by the slow clock. However, because the built-in boot program may have started, you need to reset the slow clock to the host clock source at startup. However, the host clock register requires that the written value

, respectively.Example: ADD r0, r1, r2; r0 = r1 + r2RSB r0, r1, r2; r0 = r2-r1Logical operations by bit: AND, ORR, EOR, BICNote: bitwise and, bitwise OR, bitwise OR, and notExample: BIC r0, r1, r2; r0 = r1 and not r2Register transfer operation: MOV, MVNNote: MVN is a bitwise reverse transfer.Example: MVN r0, r2; r0 = not r2Comparison: CMP, CEN, TST, TEQNote: comparison, reverse comparison, bit test, and test are equalExample: TEQ r1, r2;Note: The sequential format of operands is the result regis

address of the "/system/bin/sh" string, and then call the system () function to achieve our goal. How to find the gadgets? Although ida or objdump can be used for search, it is time-consuming and laborious. Here I recommend ROPGadget. Because level7 is compiled into the thumb command by default, we also use the thumb mode to find the gadgets: #!bash$ ROPgadget --binary=./level7 --thumb | grep "ldr r0"0x00008618 : add r0, pc ; b #0x862e ; ldr r0, [pc, #0x10] ; add r0, pc ; ldr r0, [r0] ; b #0x86

Job 1 Area exone, code, readwriteentry code32 mov r0, #100; number of times mov R1, #1 to be compared in the Register; initial two numbers mov R2, #0 loop add R2, r2, R1; add R1, R1, #1 in pairs; automatically add sub r0, R0, #1; subtract one CMP R0 from the number to be added, #0; determine whether the number of comparisons is zero BNE loop LDR R3, = resultstr R2, [R3] resultdcd 0 stopb stop Assignment 2

Tool used in the experiment: Xiao fan Simulator 1. On router R1, configure the interface, start the ospf routing process and rip, advertise the network segment, and configure route redistribution.★☆R1 ☆★☆→Router>Router> enableRouter # config terminalRouter (config) # hostname R1-jinR1-jin (config) # interface loopback 0R1-jin (config-if) # ip address 1.1.1.1 255.255.255.255R1-jin (config-if) # interface f0/0R1-jin (config-if) # ip address 10.0.0.1 255.0.0.0R1-jin (config-if) # no shutdownR1-jin

(3) Kernel/prink.c in order to provide DEBUG_LL functionality, the arch/arc/mach-processor/include/mach/debug-macro must also be perfected. S first to say the benefits, why open kernel low-level debugging functions function. After opening this macro definition, a portion of the IO map is established in the __create_page_tables of the Head.s function, as follows: #ifdef CONFIG_DEBUG_LLLdr R7, [R10, #PROCINFO_IO_MMUFLAGS] @ io_mmuflags /** Map in IO space for serial debugging.* This allows debug

This article is from and Forum: Http://bbs.51cto.com/thread-807740-1.html ThanksKwq0715Good questions ThanksLgq2358132134Answer First, topology 650) this. width = 650; "onclick = 'window. open (" http://blog.51cto.com/viewpic.php? Refimg = "+ this. src) 'border =" 0 "alt =" "src =" http://www.bkjia.com/uploads/allimg/131227/0331014241-0.jpg "/> R1 and r2 12.1.1.0/24 network segments R1 and r3 13.1.1.0/24 network segments Requirements: R1, R2, and

: The original instruction: Xchg ebx, ecx add eax, ECX P-code that do not have context rotation: Current Register Mappings Real Registers Virtual registers EAX R0 EBX R1 ECX R2 Getreg R2; R2 = ECX getreg R1; R1 = EBX SetREG R2; ECX = value of EBX SetREG R1; EBX = value of ECX getreg R2 getreg R0; R0 = EAX Add SetREG R0 P-code with context rotation (exchanged when p-code generation is complete): Before Exchange Real registers Virtual registers EAX R0 EBX R1 ECX R2 After

Tags: arm stack storageAbout multi-register load storage directives 1.LDMIA instruction, Ldmib instruction, ldmdb instruction, LDMDA directive (1) Ldmia instruction, IA means address plus 4 after each transfer (2) Ldmib instruction, address plus four before each transfer (3) Ldmdb instruction, the address before each transmission minus 4, here also pay attention to the program first to R5, or first give R8, here is obviously first give R8 (4) Ldmda instruction, after each transmission ad

Range is a class of range objects that can be defined by using the range operator "..." Or "...", ".." The generated Range objects include the start and end points. ... "The resulting Range object does not include the start and end points, the range is composed of a sequence of sequential, regular element objects, any ordered, regular set of objects, can be defined with a Range object, such as numbers, letters, strings, or even time 1, the Range object definition Copy Code code as follo

The experiment requires that the maximum minimum value be removed after sorting, and then the remainder is averaged.Sorting can be sorted with previous bubbles, and the key question is averaging. Because ARM does not have division, how should the average be asked?The simplest way is to subtract, use dividend to subtract the number, see how many times it can be reduced.However, to round up, because the registers are integers, the remainder is compared to half of the divisor, and if it is greater

, respectively.Example: Add r0, R1, R2; R0 = R1 + R2RSB r0, R1, R2; R0 = R2-r1Logical operations by bit: And, Orr, EOR, BicNote: bitwise AND, bitwise OR, bitwise OR, and notExample: Bic r0, R1, R2; R0 = R1 and not r2Register transfer operation: mov, MVNNote: MVN is a bitwise reverse transfer.Example: MVN r0, R2; R0 = Not r2Comparison: CMP, CEN, TST, TEQNote: comparison, reverse comparison, bit test, and test are equalExample: TEQ R1, R2;Note: The sequential format of operands is the result regis